Blood type is determined by the alleles coding for the antigen present on cell membranes.
The person with type AB blood has a heterozygous Rh factor.
- Half the gametes have Rh factor (+) and the other half are negative for Rh factor (-)
- Half the gametes have IA and the other half have IB
- The possible gamete combinations are IA+, IA-, IB+, IB-
The person with heterozygous type A blood is negative for Rh factor
- All gametes are negative for Rh factor (-)
- Half the gametes have IA and the other half have IO
- The possible gametes are IA-, IO-
The genotype ratio is 1:1:1:1:1:1:1:1
The phenotype ratio is 2: 2:1:1:1:1.
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Answer:
The genotype of both parents is RrYy.
The possible types of gametes would be RY, Ry, rY, and ry.
The cross would produce offspring that can have one out of four types of phenotypes:
- Round and yellow seeds (1 RRYY+ 2 RrYY +2 RRYy + 4 RrYy) = 9/16
- Wrinkled and yellow seeds (3 rrYy) = 3/16
- Round and green seeds (1 RRyy + 2 Rryy) = 3/16
- Wrinkled and green seeds (rryy) = 1/16
Thus, one out of 16 offspring would have wrinkled and green seeds.
1st conclusion: Organisms inherit two copies of each gene, one from each parent.
2nd conclusion: Organisms donate only one copy of each gene in their gametes.
Thus the two copies of each gene segregate or separate during gamete.
Hope this helpedXD
Answer:
Each granddaughter cell is haploid (n)
Explanation:
Meiosis in the parent cell with a "2n" chromosome number would produce a total of four daughter cells. Each of these daughter cells would have an "n" number of chromosomes as separation of homologous chromosomes to the opposite poles during anaphase-I reduces the chromosome number to half in the daughter cells. Also, the event of crossing over and random segregation of homologous chromosomes makes the daughter cells of meiosis genetically different from each other.
Each of these four cells enters mitosis and forms a total of eight cells. Since mitosis maintains the chromosome number, each of the eight cells would have an "n" number of chromosomes and would be haploid.