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nadezda [96]
3 years ago
9

A: If a net force greater than 0 N is applied to an electron and to a proton, which one will accelerate more? The mass of an ele

ctron is roughly 1 2000 th that of a proton. A) The electron will accelerate more than the proton. B) The proton will accelerate more than the electron. C) Both the proton and the electron will move at a constant speed. D) Both the proton and electron will accelerate by the same amount.
Physics
2 answers:
aleksandrvk [35]3 years ago
8 0

according to newton's second law , net force on an object is the product of mass of the object and the acceleration of the object. the formula is given as

F = ma               where F = net force , m = mass and a = acceleration

so acceleration can be given as

a = F/m

for same net force , the acceleration depends on the mass of the object .

greater the mass , smaller will be the acceleration and vice versa.

Since the mass of electron is smaller as compared to the mass of proton, hence the electron will accelerate more as compared to proton.

A) The electron will accelerate more than the proton

navik [9.2K]3 years ago
4 0

A) <u>the electron will accelerate more than the proton.</u>

If the net force is greater than one, SOOO Newton’s second law of motion, an object will accelerate. The mass is inversely proportional to the acceleration. The lower the mass, the faster the acceleration,

hope this helps! :)

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Answer:

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Explanation:

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When a sinusoidal wave with speed 20 m/s , wavelength 35 cm and amplitude of 1.0 cm passes, what is the maximum speed of a point
vova2212 [387]

To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion

From the definition we know that the frequency can be expressed as

f = \frac{v}{\lambda}

Where,

v = Velocity \rightarrow 20m/s

\lambda = Wavelength \rightarrow 35*10^{-2}m

Therefore the frequency would be given as

f = \frac{20}{35*10^{-2}}

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The frequency is directly proportional to the angular velocity therefore

\omega = 2\pi f

\omega = 2\pi *57.14

\omega = 359.03rad/s

Now the maximum speed from the simple harmonic movement is given by

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Then replacing,

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A garden hose has a radius of 0.0120 m, and water initially comes out at a speed of 2.88m/s. Dasha puts her thumb over the end ,
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v = 12.4 [m/s]

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A=\pi *(0.0120)^{2} \\A=4.523*10^{-4} [m]\\

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Despite the fact that you cover the inlet with the finger, the volumetric flow rate is the same.

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