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nadezda [96]
3 years ago
9

A: If a net force greater than 0 N is applied to an electron and to a proton, which one will accelerate more? The mass of an ele

ctron is roughly 1 2000 th that of a proton. A) The electron will accelerate more than the proton. B) The proton will accelerate more than the electron. C) Both the proton and the electron will move at a constant speed. D) Both the proton and electron will accelerate by the same amount.
Physics
2 answers:
aleksandrvk [35]3 years ago
8 0

according to newton's second law , net force on an object is the product of mass of the object and the acceleration of the object. the formula is given as

F = ma               where F = net force , m = mass and a = acceleration

so acceleration can be given as

a = F/m

for same net force , the acceleration depends on the mass of the object .

greater the mass , smaller will be the acceleration and vice versa.

Since the mass of electron is smaller as compared to the mass of proton, hence the electron will accelerate more as compared to proton.

A) The electron will accelerate more than the proton

navik [9.2K]3 years ago
4 0

A) <u>the electron will accelerate more than the proton.</u>

If the net force is greater than one, SOOO Newton’s second law of motion, an object will accelerate. The mass is inversely proportional to the acceleration. The lower the mass, the faster the acceleration,

hope this helps! :)

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3 0
3 years ago
Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orb
Maslowich

Answer: 58,045,522,878.8 meters

Explanation:

Ok, the data we have is

Period = T = 88 days

Radial acceleration = ar = 3.96x10^-2 m/s^2

And we know that the equation for the radial acceleration is:

ar = v^2/r = r*w^2

Where v is the velocity. r is the radius and w is the angular velocity.

And we know that:

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Now we solve this for r.

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r = (3.96x10^-2 m/s^2) /(2*3.14/7,603,200s)^2 = 58,045,522,878.8 meters

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