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Agata [3.3K]
3 years ago
15

How did Thompson´s model differ from Dalton´s model

Physics
1 answer:
Paladinen [302]3 years ago
3 0
<span>The difference between Dalton's model of the atom and Thomson's model was that Dalton's model had different elements that consist of different atoms and Thomson's model had atoms that have smaller particles called electron.

</span>
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If cells were not able to obtain amino acids, what macromolecule would not be able to be synthesized
Zielflug [23.3K]

Answer:

protein

Explanation:

protein is a very large complex macro-molecule that requires amino acids

5 0
3 years ago
"One step in the manufacture of silicon wafers used in the microelectronics industry is the melt crystallization of silicon into
nevsk [136]

Answer:

fgfgfdgdg

Explanation:

gfdgfgfgd

7 0
3 years ago
The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in
Sonja [21]

Answer:

10.16 degrees

Explanation:

Apply Snells Law for both wavelenghts

\(n_{1}sin\theta_{1} = n_{2}sin\theta_{2}\)

For red

(1.620)(sin 25.5) = (1)(sin r)

For red, the angle is 35.45degrees

For violet

(1.660)(sin 25.5) = (1)(sin v)

For violet, the angle is 45.6 degrees

The difference is 45.6- 35.45 = 10.16 degrees

3 0
3 years ago
The total electric flux from a cubical box 26.0 cm on a side is 1840 N m2/C. What charge is enclosed by the box?
vitfil [10]

The expression of the electric flux is

\Phi = \frac{Q}{\epsilon_0}

Here,

Q = Total charge enclosed in the closed surface

\epsilon_0 = Permittivity due to free space

Rearranging to find the charge,

Q = \epsilon_0 \Phi

Replacing with our values we have finally

Q = (8.85*10^{-12}F\cdot m^{-1})(1.84*10^3 N\cdot m^2/C)

Q = 1.6284*10^{-8} C (\frac{10^9nC}{1C})

Q = 0.1684nC

The charge enclosed by the box is 0.1684nC

The sign of the charge can be decided by using the direction of the flux. The charge enclosed by the cube can be calculated by using the electric flux and the permitivity of free space.

7 0
3 years ago
A horse does 910 J of work in 380 seconds while pulling a wagon. What is the power output of the horse? Round your answer to two
Alekssandra [29.7K]
2.39 Watts roughly since watts is joules per second it’s just 910j/380s
3 0
3 years ago
Read 2 more answers
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