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Slav-nsk [51]
3 years ago
13

Draw structure of oxygen, nitrogen &methane.​

Chemistry
2 answers:
Murrr4er [49]3 years ago
7 0

Answer:

\huge \purple {\mathfrak{Answer:}}

Elina [12.6K]3 years ago
4 0

See the image below-⬇⬇-

Hope this helps :D

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Number 1 please fast answer
Natasha2012 [34]

Answer:

I will give you 5

Explanation:

color chage, formation of a precipitate, formation of a gas, odor change, temperature change. are all signs of a chemical reaction

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2 years ago
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Kaila runs competitively. She would like to calculate her average running speed each time she runs. Which data should Kaila reco
Sladkaya [172]

Answer:

Start and end times; distance run.  

Step-by-step explanation:

Average speed = distance/time.

Kaila should record the distance run, the time she started, and the time she ended her run.

The difference between the start and end times gives the time for the run.

If she inserts her numbers into the formula, she will get her average running speed.  

4 0
3 years ago
Jim, Jill, Robert, and Kim each run paper chromatography on an unknown aqueous mixture. Jim gets a red band and a blue band, Jil
Romashka-Z-Leto [24]

Answer:

Robert

Explanation:

There is not more than one colour

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2 years ago
Electric power plants are the main source of:
bekas [8.4K]
The correct answer is particle pollution.
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3 years ago
At a certain temperature the vapor pressure of pure chloroform (CHCl3) is measured to be 91. torr. Suppose a solution is prepare
OleMash [197]

Answer:

P_{CCl_4}=52.43torr

Explanation:

Hello there!

In this case, sine the solution of this problem require the application of the Raoult's law, assuming heptane is a nonvolatile solute, so we can write:

P_{CCl_4}=x_{CCl_4}P_{CCl_4}^{vap}

Thus, we first calculate the mole fraction of chloroform, by using the given masses and molar masses as shown below:

x_{CCl_4}=\frac{140/153.81}{140/153.81+67.1/100.21}=0.576

Therefore, the partial pressure of chloroform turns out to be:

P_{CCl_4}=0.576*91torr\\\\P_{CCl_4}=52.43torr

Regards!

3 0
3 years ago
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