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KatRina [158]
3 years ago
15

When the number of protons and electrons are the same the atom is

Chemistry
2 answers:
KIM [24]3 years ago
7 0
I’m pretty sure it would be A, Neutral
belka [17]3 years ago
5 0

A.)Neutral. Since amount of protons and electron are equal and amount of protons cannot be changed so it is stable or neutral.

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tino4ka555 [31]

Answer:

D iced tea

Explanation:

right answers

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2 years ago
When you push or pull on something, you are using a
bearhunter [10]
The answer would be Force
6 0
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Convert the condensed structures to line angle formulas: 1. CH3CH2CH(CH3)CH2CH3 8. CH:COCH 9. CH3CH2OCH3 2. CH3CH2CH(CH2CH3)CH(C
kumpel [21]

Answer:

Attached in the photo.

Explanation:

Hello,

The answers in the attached photo. Just three things:

- In the second point a parenthesis is missing to properly understand the molecule (after the oxygen), nevertheless, I assumed it was an ether.

- In the sixth point, there's a missing hydrogen for it to be an ether as well.

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3 0
3 years ago
In an aqueous solution of a certain acid the acid is 4.4% dissociated and the pH is 3.03. Calculate the acid dissociation consta
NeX [460]

Answer:

4.1x10⁻⁵

Explanation:

The dissociation of an acid is a reversible reaction, and, because of that, it has an equilibrium constant, Ka. For a generic acid (HA), the dissociation happens by:

HA ⇄ H⁺ + A⁻

So, if x moles of the acid dissociates, x moles of H⁺ and x moles of A⁻ is formed. the percent of dissociation of the acid is:

% = (dissociated/total)*100%

4.4% = (x/[HA])*100%

But x = [A⁻], so:

[A⁻]/[HA] = 0.044

The pH of the acid can be calcualted by the Handersson-Halsebach equation:

pH = pKa + log[A⁻]/[HA]

3.03 = pKa + log 0.044

pKa = 3.03 - log 0.044

pKa = 4.39

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logKa = -pKa

Ka = 10^{-pKa}

Ka = 10^{-4.39}

Ka = 4.1x10⁻⁵

4 0
3 years ago
I need help with this!!
8_murik_8 [283]

Answer:

0.84kg of gatorade powder is needed.

Explanation:

From the question given above, we were told that the team manager mixes 0.6kg of gatorade powder with 5 gallons of water.

Now, to obtain the desired amount of the powder of gatorade needed for 7 gallons of water, we simply do the following:

If 0.6kg of gatorade powder required 5 gallons of water,

Then Xg of gatorade will require 7 gallons of water i.e

Xg of gatorade = (0.6 x 7)/5

Xg of gatorade = 0.84kg

Therefore, to maintain the same gatorade mixture, the team manager must mix 0.84kg of gatorade powder with the 7 gallons of water.

4 0
3 years ago
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