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Musya8 [376]
3 years ago
8

If 585.24 Joules of heat are added to 53.2 grams of water at 24.15oC, what will the new temp. be?

Chemistry
1 answer:
spayn [35]3 years ago
3 0
E = mct
Energy = (mass) x (specific heat capacity of water) x (change in temp)

585.24 = 53.2 x 4.2 x (X-24.15)


585.24 divided by 53.2 divided by 4.2 = X - 24.15

2.62 = X - 24.15

X= 26.77degrees C

(Specific heat capacity for water is 4.2 but is different for other liquids)
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P 4 + 5O 2 P 4 O 10 , 1.5 moles of product was made in 30 seconds. What is the rate of reaction? 0.011 g/min 210 g/min 380 g/min
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Answer: 850.0 g/min.

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  • The rate of the reaction = (ΔC/Δt) where,

ΔC is the change in concentration of reactants or products.

Δt is the change in time of the reaction proceeding.

  • The rate is needed to be calculated in (g/min).
  • We need to calculate the amount of the product in (g) via using the relation (n = mass / molar mass).
  • mass (g) = n x molar mass,
  • n = 1.5 moles and molar mass of P₄O₁₀ = 283.88 g/mol.
  • m = 1.5 x 283.88 = 425.82 g.
  • ΔC = 425.82 g and Δt = 30 s / 60 = 0.5 min.
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<em>can be approximated to 850.0 g/min.</em>

6 0
3 years ago
Read 2 more answers
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