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valentina_108 [34]
3 years ago
12

The speed of sound in an ideal gas is given by the relationship v = γRTM−−−−√ , where R - the universal gas constant = 8.314 J/m

ol⋅K ; T - the absolute temperature; M - the molar mass of the gas in kg/mol ; and γ is a characteristic of the specific gas. For air, γ = 1.4. Calculate the speed of sound in the air. Assume that air is 20% oxygen and 80% nitrogen and the temperature of air is 293 K . Express your answer to two significant figures and include the appropriate units.
Part B

While camping, you record a thunderclap whose intensity is 10−2 W/m2 . The clap reaches you 3.0 s after a flash of lightning. Assume that the thunder radiates spherically from its source. Estimate the total acoustical power generated by the bolt of lightning. Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

Explanation:

1.) v=\sqrt{\frac{yRT}{m} } \\\\=\sqrt{\frac{1.4\times8.3\times293}{0.029} }\\\\=342.64m/s

2.) 4\pi r^2I=P\\\\\\P=4\pi(vt)^2I=4\pi (342.64\times3)^2(10^{-2})=1.33\times10^5watt

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A boy runs 400m at an average speed of 4.0m/s he runs the first 200m in 40 s how long does he take to run the second 200m?
IRISSAK [1]
If he runs at the same speed he will cover next 200m in 40s
that is at the average of 4.0m
8 0
3 years ago
A lunar module weighs 12 metric tons on the surface of the Earth. How much work is done in propelling the module from the surfac
zhuklara [117]

Answer:

W=76.55 miles.metric tons

Explanation:

Given that

Weight on the earth = 12 tons

So weight on the moon =12/6 = 2 tons

 ( because at moon g will become g/6)

As we know that

F=\dfrac{K}{x^2}

Here x= 1100 miles

F 2 tons

2=\dfrac{K}{1100^2}

So

K=2.4\times 10^6

We know that

Work = F. dx

W=\int_{x_1}^{x_2}F.dx

W=\int_{1100}^{1140}\dfrac{2.4\times 10^6}{x^2}.dx

W=-2.4\times 10^6\left[\dfrac{1}{x}\right]_{1100}^{1140}

W=-2.4\times 10^6\left[\dfrac{1}{1140}-\dfrac{1}{1100}\right]

W=76.55 miles.metric tons

6 0
3 years ago
an ice cube placed in microwave melts in five minutes and it takes 3.50 kj of energy to melt it. what is the power of the microw
Artist 52 [7]

If the ice absorbed 350,000 joules in 5 minutes, then it absorbed energy
at the rate of

   (350,000 joules) / (5 x 60 seconds)  =<em>  1,166-2/3 watts</em> .

Surely the ice cube didn't absorb every joule delivered to the cooking chamber,
so the microwave oven's cooking power had to be significantly more than that.

6 0
3 years ago
Find τf, the torque about point p due to the force applied by the achilles' tendon.
Luba_88 [7]
The formula for the torque is
<span>τf = p F
where
</span><span>τf is the torque
p is the distance where the force is applied by the tendon
F is force applied by the tendon

If there are given values, substitute in the equation and solve for the torque.</span>
3 0
3 years ago
A car is cruising at a steady speed of 35 mph. Suddenly, a cuddly puppy runs out into the road. The driver takes 1.7 seconds to
Schach [20]

Answer:

The distance traveled is 0.037 mi

Explanation:

The equation for the position and velocity of an accelerated object is:

x = x0 + v0 * t + 1/2 * a * t²

v = v0 + a * t

where

x = position at time t

x0 = initial position

t = time

a = acceleration

v0 = initial velocity

If the velocity is constant, then a = 0 and the position will be:

x = x0 + v * t where "v" is the velocity

First, let´s find the distance traveled until the driver push the brake:

The speed is constant. Then:

x = x0 + v * t (considering the origin of the reference system to be located at the point at which the driver sees the puppy, x0 = 0)

x = 35 mi/h (1 h / 3600 s) * 1.7 s = 0.017 mi

Then, the drivers moves with constant acceleration until the car stops (v = 0)

From the equation for velocity:

v = v0 + a * t

Since v = 0, we can obtain the acceleration of the car until it stops. With that acceleration, we can calculate how much distance the car moves before it stops.

0 = v0 + a * t

-v0 / t = a

-35 mi/h (1 h / 3600s) / 4.0 s = a

a = -2.4 x 10⁻³ mi/s²

The distance traveled will be:

x = x0 + v0 * t + 1/2 * a * t²

Now x0 will be the distance traveled before the driver slows down.

x = 0.017 mi + 35 mi/h (1 h / 3600s) * 4 s + 1/2 * ( -2.4 x 10⁻³ mi/s²) * (4s)²

x = 0.037 mi

6 0
3 years ago
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