Answer:
A) Catalyst-Mn2+
Intermediates Mn3+ and Mn4+
Rate determining step is the reaction of Ce4+ with Mn2+
B) The reaction will be a termolecular reaction in the absence of the catalyst. It will be difficult for the two Ce2+ and Ti+ to collide in the correct orientation for reaction to occur in the absence of the catalyst hence the reaction will be slow in the absence of the catalyst.
C) Both catalyst and reactants are ions in solution hence it is a homogeneous catalysis
Explanation:
The catalyst is the specie that is regenerated at the end of a reaction. This specie is Mn2+.
Intermediates are transient species that only occur in elementary steps of a complex reaction mechanism.
The species involved in the rate determining step enter into the rate equation since the rate determining step is the slowest step in a complex reaction mechanism and determine the overall rate of reaction. The rate equation rate = k[Ce^4+][Mn^2+] confirms that the first step is the rate determining step in the overall reaction mechanism.
Electrons, everything is pretty much based around the likeliness of electrons to be swapped or shared between atoms
Answer:
Kc = 9.52.
Explanation:
<em>A + 2B ⇌ C,</em>
Kc = [C]/[A][B]²,
Concentration: [A] [B] [C]
At start: 0.3 M 1.05 M 0.55 M
At equilibrium: 0.3 - x 1.05 - 2x 0.55 + x
0.14 M 1.05 - 2x 0.71 M
- For the concentration of [A]:
∵ 0.3 M - x = 0.14 M.
∴ x = 0.3 M - 0.14 M = 0.16 M.
∴ [B] at equilibrium = 1.05 - 2x = 1.05 M -2(0.16) = 0.73 M.
<em>∵ Kc = [C]/[A][B]²</em>
∴ Kc = (0.71)/(0.14)(0.73)² = 9.5166 ≅ 9.52.
Answer: el estudio de la síntesis, estructura, reactividad y propiedades del diverso grupo de compuestos químicos construidos principalmente de carbono
Explanation:Hope I helped:)
<u>Answer:</u> The molarity of
ions in the solution is 0.306 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:

We are given:
Mass of solute
= 15.6 g
Molar mass of
= 295.6 g/mol
Volume of solution = 345 mL
Putting values in above equation, we get:

As, 1 mole of
produces 1 mole of copper (II) ions and 2 moles of nitrate ions.
So, molarity of
ions = (2 × 0.153) = 0.306 M
Hence, the molarity of
ions in the solution is 0.306 M