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allsm [11]
4 years ago
9

It takes

Chemistry
1 answer:
poizon [28]4 years ago
6 0

The maximum wavelength that can break a Cl-Cl bond is 494 nm.

<em>Energy to break 1 Cl-Cl bond </em>

Energy = (242 kJ/1 mol) × (1000 J/1 kJ) × (1 mol/6.022 × 10²³ bonds)

= 4.019 × 10⁻¹⁹ J/bond

<em>Wavelength of photon </em>

<em>E</em> = h<em>f</em> = (h<em>c</em>)/λ

λ = (h<em>c</em>)/E = (6.626 × 10⁻³⁴ J × 2.998 × 10⁸ m·s⁻¹)/(4.019 × 10⁻¹⁹ J) = 4.94 × 10⁻⁷ m = 494 nm

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Thallium(I) is oxidized by cerium(IV) as follows:
miskamm [114]

Answer:

A) Catalyst-Mn2+

Intermediates Mn3+ and Mn4+

Rate determining step is the reaction of Ce4+ with Mn2+

B) The reaction will be a termolecular reaction in the absence of the catalyst. It will be difficult for the two Ce2+ and Ti+ to collide in the correct orientation for reaction to occur in the absence of the catalyst hence the reaction will be slow in the absence of the catalyst.

C) Both catalyst and reactants are ions in solution hence it is a homogeneous catalysis

Explanation:

The catalyst is the specie that is regenerated at the end of a reaction. This specie is Mn2+.

Intermediates are transient species that only occur in elementary steps of a complex reaction mechanism.

The species involved in the rate determining step enter into the rate equation since the rate determining step is the slowest step in a complex reaction mechanism and determine the overall rate of reaction. The rate equation rate = k[Ce^4+][Mn^2+] confirms that the first step is the rate determining step in the overall reaction mechanism.

8 0
4 years ago
Based on the current atomic theory most chemical reaction take place as a result of the interactions of which sub- atomic partic
icang [17]
Electrons, everything is pretty much based around the likeliness of electrons to be swapped or shared between atoms
6 0
3 years ago
A mixture initially contains A, B, and C in the following concentrations: [A] = 0.300 M , [B] = 1.05 M , and [C] = 0.550 M . The
Hunter-Best [27]

Answer:

Kc = 9.52.

Explanation:

  • The equilibrium system:

<em>A + 2B ⇌ C,</em>

Kc = [C]/[A][B]²,

Concentration:     [A]                [B]              [C]

At start:               0.3 M         1.05 M        0.55 M

At equilibrium:   0.3 - x        1.05 - 2x     0.55 + x

                            0.14 M        1.05 - 2x      0.71 M

  • For the concentration of [A]:

∵ 0.3 M - x = 0.14 M.

∴ x = 0.3 M - 0.14 M = 0.16 M.

∴ [B] at equilibrium = 1.05 - 2x = 1.05 M -2(0.16) = 0.73 M.

<em>∵ Kc = [C]/[A][B]²</em>

∴ Kc = (0.71)/(0.14)(0.73)² = 9.5166 ≅ 9.52.

4 0
4 years ago
¿Qué estudia la química orgánica?
Scorpion4ik [409]

Answer: el estudio de la síntesis, estructura, reactividad y propiedades del diverso grupo de compuestos químicos construidos principalmente de carbono

Explanation:Hope I helped:)

8 0
3 years ago
An aqueous solution is prepared by dissolving 15.6 g of Cu(NO3)2 ⋅ 6 H2O in water and diluting to 345 mL of solution. What is th
Vladimir [108]

<u>Answer:</u> The molarity of NO_3^- ions in the solution is 0.306 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (Cu(NO_3)_2.6H_2O) = 15.6 g

Molar mass of (Cu(NO_3)_2.6H_2O) = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M

As, 1 mole of (Cu(NO_3)_2.6H_2O) produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of NO_3^- ions = (2 × 0.153) = 0.306 M

Hence, the molarity of NO_3^- ions in the solution is 0.306 M

3 0
3 years ago
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