What is the name of the compound CrPO4 • 5H2O?
1 answer:
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<h3>Answer:</h3>
- Because the water doesn't have to reach all the way to the top.
Taking into account the reaction stoichiometry and definition of limiting reactant, AgNO₃ will be the limiting reagent.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Cu: 1 mole
- AgNO₃: 2 moles
- Ag: 2 moles
- Cu(NO₃)₂: 1 mole
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
<h3>Limiting reagent in this case</h3>To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Cu reacts with 2 moles of AgNO₃, 1.8 moles of Cu reacts with how many moles of AgNO₃?
<u><em>amount of moles of AgNO₃= 3.6 moles</em></u>
But 3.6 moles of AgNO₃ are not available, 2 moles are available. Since you have less moles than you need to react with 1.8 moles of Cu, AgNO₃ will be the limiting reagent.
<h3>Summary</h3>In summary, AgNO₃ will be the limiting reagent.
Learn more about the reaction stoichiometry:
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Answer:
a) 40,75 atm
b) 30,11 atm
Explanation:
The Ideal Gas Equation is an equation that describes the behavior of the ideal gases:
PV = nRT
where:
- P = pressure [atm]
- V = volume [L]
- n = number of mole of gas [n]
- R= gas constant = 0,08205 [atm.L/mol.°K]
- T=absolute temperature [°K]
<em>Note: We can express this values with other units, but we must ensure that the units used are the same as those used in the gas constant.</em>
The truncated virial equation of state, is an equation used to model the behavior of real gases. In this, unlike the ideal gas equation, other parameters of the gases are considered as the <u>intermolecular forces</u> and the <u>space occupied</u> by the gas
where:
- v is the molar volume [L/mol]
- B is the second virial coefficient [L/mol]
- P the pressure [atm]
- R the gas constant = 0,08205 [atm.L/mol.°K]
a) Ideal gas equation:
We convert our data to the adecuate units:
n = 5 moles
V = 3 dm3 = 3 L
T = 25°C = 298°K
We clear pressure of the idea gas equation and replace the data:
PV = nRT ..... P = nRT/V = 5 * 0,08205 * 298/3 =40,75 atm
b) Truncated virial equation:
We convert our data to the adecuate units:
n = 5 moles
V = 3 dm3 = 3 L
T = 25°C = 298°K
B = -156,7*10^-6 m3/mol = -156,7*10^-3 L/mol
We clear pressure of the idea gas equation and replace the data:
and v = 3 L/5 moles = 0,6 L/mol