Answer:
3.85 × 10²³ molecules CO
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Compounds
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
<em>Identify</em>
[Given] 17.9 g CO
[Solve] molecules CO
<u>Step 2: Identify Conversions</u>
Avogadro's Number
[PT] Molar Mass of C: 12.01 g/mol
[PT] Molar Mass of O: 16.00 g/mol
Molar Mass of CO: 12.01 + 16.00 = 28.01 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Divide/Multiply [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
3.8484 × 10²³ molecules CO ≈ 3.85 × 10²³ molecules CO