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nikitadnepr [17]
3 years ago
15

This is something easy can someone please finish this one. i'll give brainliest.

Chemistry
2 answers:
Ainat [17]3 years ago
4 0

Answer:

B B C A C B A A C C

Explanation:

jk it was a big guess

Flauer [41]3 years ago
4 0

Answer:

1. C maybe

2. C

3. B

4. A

5. A

6. B

7. C

8. A

9. C

10. A

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To test paint quality, scientists designed an experiment where the paint was exposed to temperatures ranging from 260 degrees Ce
pishuonlain [190]

Answer:

The independent variable is the temperature to which the paint and materials are exposed

The dependent variable is the presence of peeling and cracking of the paint

The constant rates are the paint and material used for each trial

Explanation:

The treatment the to which the paint is subjected = Temperatures from 260 °C  to 650 °C

The method of determining the paint quality = By peeling and cracking

The types of paint and materials used = The same paint and material

The independent variable is the variable suspected as the cause of the effect being studied. It is the variable introduced as a treatment

In the question, given that the paint is subjected to different temperatures from between 260°C to 650 °C, the temperature changes introduced is the independent variable

Therefore;

The independent variable = The temperature to which the paint and materials are exposed to

The dependent variable is the effect variable. It is the variable of the property being investigated and it is also the variable that is measured in the investigation

In the question, given that the after heating the paint and material, the scientist check for peeling and cracking, the dependent variable is the occurrence of cracking and peeling at a given temperature

Therefore;

The dependent variable = The presence of peeling and cracking of the paint

The constant rate(s) are variables which are kept constant during the investigation, under the different treatments

The constant rate(s) in the tests are the paint and material, which were kept the same for each trial to reduce the effect of underlying factors that may impact on the result and obscure the relationship between the dependent and independent variables

Therefore;

The constant rate are the paint and material used for each trial

8 0
3 years ago
Which electron in sulfur is most shielded from nuclear charge?
natima [27]

Answer: 3p Orbitals

Explanation:

Electrons present in the 3p orbitals are farthest from the nucleus. Therefore, the electrons present in the 3p orbital will be shielded by the electrons present in the inner orbitals. Hence, 3p orbital in sulfur is most shielded from the nuclear charge".

5 0
3 years ago
Please help me. ? :)
BaLLatris [955]

Answers and explanation:

To answer these questions you use a periodic table.

A is In because it has 49 protons and In is element number 49.

B is 27 because Co is element number 27.

C is 73 because Ta is element number 73.

D is 49 because the number of electrons in an atoms is always equal to the number of protons.

E is 56 because the atomic number of Ba is 56.

F is 54 because 56 - 54 = 2. The charge is equal to the number of protons minus the number of electrons.

G is 66. The number of neutrons is equal to the atomic mass minus the number of protons. 115 - 49 = 66.

H is 108 because 181 - 73 = 108.

I is 32. The atomic mass of an element is equal to the amount of protons plus the amount of neutrons. So 16 + 16 = 32.

3 0
4 years ago
If a mineral has a metallic shine and scratches, which of its properties are being measured? Choose the two correct answers.
zzz [600]
If a mineral has a metallic shine and scratches, which of its properties are being measured?
Choose the two correct answers.

magnetism

hardness

cleavage

luster

Answer: hardness and luster
8 0
3 years ago
The molar mass of argon is 40g / mol what is the molar mass of a gas if it effuses at 0.91 times the speed of argon gas
Effectus [21]
To determine the molar mass of the unknown gas, we use Graham's Law of Effusion where it relates the effusion rates of two gases with their molar masses. It is expressed as r1/r2 = √M2/M1. We calculate as follows:

Let 1 = argon gas
      2 = unknown gas

r2 = 0.91r1
r1/r2 = 1/0.91

1/0.91 = √M2/M1 = √M2/40
M2 = 48.30 g/mol
8 0
4 years ago
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