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cluponka [151]
4 years ago
14

Mateo has a fish in a fish tank. Every day, he feeds the fish flakes of food. He also changes the water as necessary. He has an

aerator that pumps bubbles into the tank. Which sentence shows that the fish has a place to live? Mateo has a fish in a fish tank. Every day, he feeds the fish flakes of food. He also changes the water as necessary. He has an aerator that pumps bubbles into the tank.
Chemistry
2 answers:
dimaraw [331]4 years ago
4 0

Answer:

He has an aerator that pumps bubbles into the tank

Explanation:

suter [353]4 years ago
3 0

Answer:c I guess

Explanation:

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Create a flow chart that shows techniques for separation of the mixture sand, water, and ethanol.
Radda [10]
well I know that sand do disappear in water.And sand isnt the the right thing for gowing plants.And sand will hold water
4 0
3 years ago
How many atoms of gold are in a pure gold coin weighing 12.0g?
grigory [225]
12.0g x 1 mol / 63.546g = 0.188839581mol 

<span>So, for every 1 mole, we have 6.022 x 10^23 of whatever we're measuring. This gives us a conversion factor of (1 mole / 6.022 x 10^23 atoms) or (6.022 x 10^23 atoms / 1 mole).
</span>
0.188839581 mol x (6.022 x 10^23 atoms) / 1 mol = 1.137191955 x 10^23 

<span>Remember from before that we are limited to 3 significant figures. Since our calculations are complete, we can now round down to: 1.14 x 10^23 </span>

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3 0
3 years ago
A mixture 21.7 g NaCl 3.74 g kcl and 9.76 g licl how many moles of nacl are in this mixture
slava [35]
Moles (mol) = mass (g) / molar mass (g/mol)

Mass of NaCl = 21.7 g
Molar mass of NaCl = <span>58.4 g/mol
Hence, moles of NaCl = </span>21.7 g / 58.4 g/mol = 0.372 mol

Hence moles of NaCl in the mixture is 0.372 mol.

Let's assume that mixture has only given compounds and free of impurities.
Then, we can present this as a mole percentage.

mole % = (moles of desired substance / Total moles of the mixture) x 100%

Hence,
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%

Total moles of mixture = moles of NaCl + KCl + LiCl

Mass of KCl = 3.74 g 
Molar mass of NaCl = 74.6 g/mol
Hence, moles of NaCl = 3.74 g  / 74.6 g/mol = 0.050 mol

Mass of NaCl = <span>9.76 g
</span>Molar mass of NaCl = 42.4 g/mol
Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol

Total moles =  0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol

mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
                           = (0.372 mol / 0.652 mol) x 100%
                           = 57.06% 

Hence, mixture has 57.06% of NaCl as the mole percentage.
8 0
3 years ago
How many mL of a 6 M NaOH stock solution is needed in order to prepare 500 mL of a 0.2 M NaOH solution?
WITCHER [35]

Answer:

The right answer is "16.67 mL".

Explanation:

Given:

Molarity of NaOH,

M_1=6 \ M

M_2=0.2 \ M

Volume of NaOH,

V_1=V \ mL

V_2=500 \ mL

As we know, the equation,

⇒ M_1V_1=M_2V_2

On putting the values, we get

⇒ 6\times V=0.2\times 500

⇒ 6\times V=100

⇒        V=\frac{100}{6}

⇒            =16.67 \ mL      

3 0
3 years ago
State two types of plastics and their uses.​
Svetllana [295]

Thermoplastic and thermosetting

thermoplastic:- they are easily molded and extruded into films, fibres and packaging.For eg. PVC

thermosetting:-they are hard and durable and can be used for aircraft parts,tires and auto parts .For eg. phenolic resins.

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7 0
2 years ago
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