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vfiekz [6]
3 years ago
13

1. what planet/star is the center of the solar system

Physics
1 answer:
puteri [66]3 years ago
8 0
I need more details like r u reading from something 

You might be interested in
Simple question (Serious answers)
yuradex [85]

Answer: 1

Explanation:

hey i m Lola 16 years old  hope this helped you ! :D

7 0
3 years ago
One scientist suggests that out of the different possible locations, they should design the model and build it at the equator re
Anika [276]

Answer:

B.

I think.

Explanation:

Mars doesn't have that much of an atmosphere!

Have a great day!

7 0
3 years ago
A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of
SVEN [57.7K]

Answer:

Acceleration due to gravity is 20 m/sec^2

So option (E) will be correct answer

Explanation:

We have given length of the pendulum l = 2 m

Time period of the pendulum T = 2 sec

We have to find acceleration due to gravity g

We know that time period of pendulum is given by

T=2\pi \sqrt{\frac{l}{g}}

2=2\times 3.14 \sqrt{\frac{2}{g}}

0.3184= \sqrt{\frac{2}{g}}

Squaring both side

0.1014= {\frac{2}{g}}

g=19.71=20m/sec^2

So acceleration due to gravity is 20 m/sec^2

So option (E) will be correct answer.

8 0
3 years ago
A pendulum is made by letting a 4 kg mass swing at the end of a string that has a length of 1.5 meter. The maximum angle that th
olga nikolaevna [1]

Answer:

Approximately 7.8\; \rm J.

Explanation:

The change in the gravitational potential energy of the pendulum is directly related to the change in its height.

Refer to the sketch attached. The pendulum is initially at \rm P_2. Its highest point is at P_1. The length of segment \rm BP_2 gives the change in its height.

The lengths of \rm AP_1 and \rm AP_2 are simply the length of the string, 1.5\; \rm m. To find the length of \rm BP_2, start by calculating the length of \rm AB.

\rm AB forms a leg in the right triangle \rm \triangle AP_1B. Besides, it is adjacent to the 30^\circ angle \rm P_1\hat{A}B. Its length would be:

\rm AB = 1.5 \times \cos(30^\circ) \approx 1.30\; \rm m.

The length of \rm BP_2 would thus be

\rm BP_2 = AP_2 - AB = 1.5 - 1.30 \approx 0.20\; \rm m.

The change in gravitational potential energy can be found with the equation

\Delta \mathrm{GPE} = m \cdot g \cdot \Delta h. In this equation,

  • m is the mass of the object,
  • g \approx 9.81\; \rm N \cdot kg^{-1} near the surface of the earth, and
  • \Delta h is the change in the object's height.

In this case, m = 4\; \rm kg and \Delta h \approx 0.20\; \rm m. Therefore:

\Delta \mathrm{GPE} = 4 \times 9.81 \times 0.20 \approx 7.8\; \rm J.

6 0
3 years ago
A spring is hanging from the ceiling. When a 250 gram of mass is attached to the free end, the spring elongates by 5 cm. The spr
lord [1]

Answer:

k = 49 N/m

Explanation:

Given that,

Mass, m = 250 g = 0.25 kg

When the mass is attached to the end of the spring, it elongates 5 cm or 0.05 m. We need to find the spring constant. Let it is k.

The force due to mass is balanced by its weight as follows :

mg=kx

k=\dfrac{mg}{x}\\\\k=\dfrac{0.25\times 9.8}{0.05}\\\\k=49\ N/m

So, the spring constant of the spring is 49 N/m.

8 0
3 years ago
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