Answer:
26325 m\s
Explanation:
Data:
v = ?
f = 117 Hz
w = 225
Formula:
v = fw
Solution:
v = ( 117)(225)
v = 26325 m\s <em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
Therefore, option A is correct option.
Given,
Mass m = 14g
Volume= 3.5L
Temperature T= 75+273 = 348 K
Molar mass of CO = 28g/mol
Universal gas constant R= 0.082057L
Number of moles in 14 g of CO is
n= mass/ molar mass
= 14/28
= 0.5 mol
As we know that
PV= nRT
P × 3.5 = 0.5 × 0.082057 × 348
P × 3.5 = 14.277
P = 14.277/3.5
P = 4.0794 atm
P = 4.1 atm.
Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
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Answer:
might collapse
Explanation:
y'all r too heavy and tht shi will collapse and all y'all would die
Answer:
Explanation:
Given
mass of Flywheel 
mass of bus 
radius of Flywheel 
final speed of bus 
Conserving Energy i.e.
0.9(Rotational Energy of Flywheel)= change in Kinetic Energy of bus
Let 
be the angular velocity of Flywheel
