Apparent magnitude depends mainly on the brightness of the object as seen from an observer on Earth. This is taken into account without the effects of the atmosphere.
I think it means doing work in physics
Answer:
M g H / 2 = M g L / 2 initial potential energy of rod
I ω^2 / 2 = 1/3 M L^2 * ω^2 / 2 kinetic energy attained by rod
M g L / 2 = 1/3 M L^2 * ω^2 / 2
g = 3 L ω^2
ω = (g / (3 L))^1/2
Based on my information, this would actually be representing
"the average kinetic energy of water particles". So, as you take notice that where this temperature is being located, and also, how this would be

°C, this would make more sense for this to be representing as <span>the
average kinetic energy of water particles.</span>
Answer:
437.5Kjoules
Explanation:
K.E=half multiply by mass multiply by square of velocity
=437.5Kjoules