hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )
where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )
where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )
where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.
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Answer:
the inevitable elimination from a habitat of one of two different species with identical needs for resources.
Explanation:
Answer:
2.05 x 10²⁴ molecules
Explanation:
The balanced equation for the chemical reaction is the following:
2 HCl + Mg → MgCl₂ + H₂
According to the equation, 2 moles of HCl are required to react with 1 mol of magnesium (Mg), so the moles of HCl required to react with 1.7 mol Mg are calculated as follows:
moles HCl = 1.7 mol Mg x 2 mol HCl/mol Mg = 3.4 mol HCl
We know that 1 mol of any compound is equal to 6.022 x 10²³ molecular entities, so we convert the moles of HCl to molecules as follows:
molecules HCl = 3.4 mol HCl x 6.022 x 10²³ molecules/1 mol = 2.05 x 10²⁴ molecules
Answer:
Ammonia
Explanation:
I believe that ammonia is the correct answer to this question.
The number of liters produced when 126g of glucose is completely reacted with O2 is calculated as follows
find the moles of C6H12O6 used that is moles = mass /molar mass
= 126g /180 g/mol = 0.7 moles
from the equation
C6H12O6 +6O2 = 6CO2 +6 H2O
the reacting ratio of C6H12O6 to Co2 is 1:6 therefore the moles of CO2 = 0.7 x6/1= 4.2 moles
At STP 1 moles of a gas = 22.4 L
what about 4.2 L = how many liters
cross multipication
= (4.2moles x 22 .4 L)/ 1mole = 94.1 L