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3 years ago

Identify the number of each type of atom in this formula 5C12H22O11wdym

1 answer:

6 0

There are 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms in one molecule of C12H22O11.
In five molecules there are 60 carbon atoms, 110 hydrogen atoms, and 55 oxygen atoms.

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How many valence electrons are in a stable ion of a period 4 metal?

marusya05 [52]

What kind of metal is it

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3 years ago

Need help answering

svp [43]

Answer:

Your answer would be E

Explanation:

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3 years ago

The water in a pressure cooker boils at a temperature greater than 100°C because it is under pressure. At this higher temperatur

vazorg [7]

Answer:

the activation energy Ea = 179.176 kJ/mol

it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

Explanation:

From the given information

$T_1 = 100^0 C = 100+273 = 373 \ K \\ \\ T_2 = 113^0 C = 113 + 273 = 386 \ K$

$R_1 = \dfrac{1}{7}$

$R_2 = \dfrac{1}{49}$

Thus; $\dfrac{R_2}{R_1} = 7$

Because at 113.0°C; the rate is 7 time higher than at 100°C

Hence:

$In (7) = \dfrac{Ea}{8.314}( \dfrac{1}{373}- \dfrac{1}{386})$

1.9459 = $\dfrac{Ea}{8.314}* 9.0292 *10^{-5}$

$1.9459*8.314 = Ea * 9.0292*10^{-5}$

$16.1782126= Ea * 9.0292*10^{-5}$

$Ea = \dfrac{16.1782126}{ 9.0292*10^{-5}}$

Ea = 179.176 kJ/mol

Thus; the activation energy Ea = 179.176 kJ/mol

here;

$T_2 = 386 \ K \\ \\T_1 = (89.8 + 273)K = 362.8 \ K$

$In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})$

$In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})$

$In (\dfrac{R_2}{R_1}) = 0.00357$

$\dfrac{R_2}{R_1}= e^{0.00357}$

$\dfrac{R_2}{R_1}= 1.0035$

where ;

$R_2 = \dfrac{1}7{}$

$R_1 = \dfrac{1}{t}$

Now;

$\dfrac{t}{7}= 1.0035$

t = 7.0245 mins

Therefore; it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

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3 years ago

Sara is making an omelet. She cracks open 6 eggs and places them in a bowl. She adds some milk, salt, and pepper to the eggs and

Sunny_sXe [5.5K]

Answer: Well then I guess Sara is having a good breakfast

Explanation: what was the point of this question?

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4 years ago

The half-life of carbon-14 is about 6000 years. assume that a sample of charcoal is formed by burning of living wood 15,000 year

zimovet [89]

The daughter isotope has an atomic number one less than the parent and a mass number two less. : A. : 1 20) The half-life of carbon-14 is about 6000 years. Assume that a sample of charcoal formed byburning of living wood 15,000 years ago. How much of the original carbon-14 would remain today? A) more than one-half

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3 years ago