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Sedbober [7]
3 years ago
9

In 1897 the Swedish explorer Andree tried to reach the North Pole in a balloon. The balloon was filled with hydrogen gas. The hy

drogen gas was prepared from iron splints and diluted sulfuric acid. The reaction is given below.Fe(s) + H2SO4(aq) FeSO4(aq) + H2(g)The volume of the balloon was 4870 m3 and the loss of hydrogen gas during filling was estimated at 20.%. What mass of iron splints and 95% (by mass) H2SO4 were needed to ensure the complete filling of the balloon? Assume a temperature of 0°C, a pressure of 1.0 atm during filling, and 100% yield.iron splints = ____kg95% sulfuric acid =_____kg
Chemistry
1 answer:
vovangra [49]3 years ago
6 0

Answer:

iron = 15000 kg 95% sulfuric acid = 27646.32 kg

Explanation:

The molar volume to a gas is 22.4 L, which means that a mole of a given gas at 0°C and 1 atm will have a volume os 22.4 L.

1 m3 - 1000 L

4870 m3 - x

x = 4870 * 1000 = 4.87 *10^6 L

1 mole - 22.4 L

y mole - 4.87 * 10^6 L

y = \frac{4.87 * 10^6}{22.4} = 2,17 *10^5 moles (if 100% of the H2 is used)

as 20% of it is lost, we need to know how much more we need to use.

80% - 2.17 * 10^5 moles

100% - z

z = \frac{2.17* 10^7}{80} = 2,68*10^5 moles

so we would need 2.68*10^5 moles of iron and sulfuric acid.

1 mole of iron - 56 *10^-3 kg

2.68*10^5 moles - t

t= 2.68*56 *10^2 = 15000 kg

1 mole of sulfuric acid - 98 * 10^-3 kg

2.68*10^5 - u

u = 2.68*98 *10^2 = 26264 kg (if 100%)

95% - 26264 kg

100% - v

v = \frac{26264 * 100}{95} = 27646.32 kg

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3 years ago
At 25 °C, only 0.0990 mol of the generic salt AB3 is soluble in 1.00 L of water. What is the Ksp of the salt at 25 °C? AB3(s)↽−−
maksim [4K]

Answer:

Ksp=2.59x10^{-3}

Explanation:

Hello,

In this case, given the 0.0990 moles of the salt are soluble in 1.00 L of water only, we can infer that the molar solubility is 0.099 M. Next, since the dissociation of the salt is:

AB_3\rightleftharpoons A^{3+}+3B^-

The concentrations of the A and B ions in the solution are:

[A]=0.099 \frac{molAB_3}{L}*\frac{1molA}{1molAB_3}  =0.0099M

[B]=0.099 \frac{molAB_3}{L}*\frac{3molB}{1molAB_3}  =0.000.297M

Then, as the solubility product is defined as:

Ksp=[A][B]^3

Due to the given dissociation, it turns out:

Ksp=[0.099M][0.297M]^3\\\\Ksp=2.59x10^{-3}

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4 0
3 years ago
How does plants react with no scratch?
Andreas93 [3]

Answer:

You see, plants need energy to grow and grow and grow. They use energy from sunlight to make a simple sugar, glucose. Whenever the plant needs energy, it can chomp a little glucose off of the starch.

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Explanation:

3 0
3 years ago
An atom of 132sn has a mass of 131. 917760 amu. mass of1h atom = 1. 007825 amu mass of a neutron = 1. 008665 amu. calculate the
Lelechka [254]

The mass defect in amu/atom is 11.928.

The mass defect is the discrepancy between the nucleus of an atom's anticipated mass and its actual mass. This discrepancy is due to the binding energy of a system, which might manifest as excess mass.

The nucleus must be robustly spherical as expected for a doubly magical nucleus because the stripped neutron fell into a distinct orbital shell above the closed inner shells of tin-132 after the researchers examined the energy and angular distribution of the particles.

Mass of atom = 131.917760 amu

Mass of proton = 1.007825 amu

Mass of neutron = 1.008665 amu

Sn atom has 50 protons and 69 neutrons.

Mass defect = Mp + Mn - MA

                    = 50 × 1.007825 + 69 × 1.008665 - 131.917760

                    = 50.39125 + 69.597885 - 131.917760

                    = 11.928 amu/atom

Therefore, the mass defect in amu/atom is 11.928.

Learn more about mass defects here:

brainly.com/question/11410788

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