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Sholpan [36]
3 years ago
13

A gas occupies a volume of 4.50 L at 44 kPa. What would be the new volume at 50 kPa?

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
5 0

Explanation:

P1= 44 kpa

P2= 50 kpa

V1= 4.50 L

V2= ?

P1 V1= P2 V2

44 × 4.50 = 50 × V2

198= 50 × V2

V2 = 198/ 50

V2= 3.96 L "the new volume"

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Alkanes

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How many grams of ethylene glycol (C2H6O2) must be added to 1.15 kg of water to produce a solution that freezes at -4.46°C?
jok3333 [9.3K]

Answer:

232.5 g C2H6O2

Explanation:

The equation you need to use here is ΔTf = i Kf m

Since pure water freezes at 0 C, your ΔTf is just 4.46 C

i = 1 (ethylene glycol is a weak electrolyte)

Kf = molal freezing constant, which for water is 1.86 C/m

m = molality = x mols C2H6O2 / 1.15 kg H2O (don't know the moles of ethylene glycol we're dissolving yet)

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4.46 C = 1.86 C/m (x mol C2H6O2 / 1.15 kg H2O)

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