The appropriate response is false. Cathode-beam ray does not deliver pictures on the guideline of instigated emf. The cathode-ray is a high-vacuum tube in which cathode beams deliver an iridescent picture on a fluorescent screen, utilized mostly in TVs and workstations.
<span>The wires are suspended diagonally, meaning the tension in each is directed diagonally as well (along the wire). We can, however, talk about the horizontal and vertical components of the tension force. The horizontal tension force in each wire is Tcosθ, while the vertical tension force is Tsinθ.
The horizontal tension forces balance one another, because the wires are pulling in opposite directions. This means Tcosθ=Tcosθ, which is obvious but not very helpful. If you look at the vertical tension forces on the other hand, you can see that they must balance the weight of the body for the system to be in equilibrium. In other words:
Tsinθ+Tsinθ=mg
You're given enough information in the question to solve for T using this equation!</span>
Consider horizontal component:
Using the formula:v2=u2+2a<span>s</span>
<span>0=(16sin<span>470</span><span>)2</span>+2(−9.81)s</span><span>s=6.98m</span><span>=7.0m(2s.f.)</span>The maximu height from the ground is 8.5m
Answer:
(a) 
(b) 
Explanation:
We will take ground level as origin and upward is positive direction
the givens are
Part (a)
To find the final velocity we use the kinematic equation
So
Part (b)
To find time of rock trip until it touches the ground we will use simple kinematic equation or simple motion equation
Notice that we substituted vf with negative sign because its direction is downwards
Answer: let's see, so it's a 1/4 chance of getting it right, hope your odds are good, have a wonderful day
Explanation:
:D
