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Lesechka [4]
3 years ago
5

The frequency of a wave is 250hz. What is the period

Physics
1 answer:
antoniya [11.8K]3 years ago
8 0

Answer:

Hope it helps for you :)))))

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Someone please help me! And I will mark you as brainlist!!
Ronch [10]

Answer:

1. G.P.E = 24 J

2. center of mass

Explanation:

Given the following data;

Mass = 2kg

Height, h = 1.2m

Acceleration due to gravity = 9.8 N/kg or m/s².

To find the gravitational potential energy;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

  • G.P.E represents potential energy measured in Joules.
  • m represents the mass of an object.
  • g represents acceleration due to gravity measured in meters per seconds square.
  • h represents the height measured in meters.

Substituting into the formula, we have;

G.P.E = 2*1.2*9.8

G.P.E = 23.52 to 2 S.F = 24 Joules.

Translation kinetic energy is defined as the energy of a system due to the motion of the system’s center of mass. The center of mass is typically where the mass of the object or particle is concentrated.

6 0
3 years ago
Help ~~~ science question
lakkis [162]
Where is the message
6 0
3 years ago
Pls tell the answer asap
Rzqust [24]
The maximum force acts between B and C as the graph is steepest showing maximum deceleration
5 0
3 years ago
A box of mass 13kg sits on a table with a coefficient of static friction of 0.85. What is the maximum force of static friction?
Alexus [3.1K]

Answer:

108.3 N

Explanation:

The maximum force of static friction acting on the box is given by:

F=\mu N

where

\mu = 0.85 is the coefficient of static friction

N is the normal reaction of the table on the box

Since the box is in equilibrium along the vertical direction, the normal reaction N is equal to the weight of the box, so:

N=mg=(13 kg)(9.8 m/s^2)=127.4 N

And so, the maximum force of static friction is

F=(0.85)(127.4 N)=108.3 N

7 0
3 years ago
A stationary 0.750kg ball is thrown up by doing 2.50J of work on it. What is the velocity of the ball?
Lena [83]

When a ball is thrown up by doing work, the velocity of the ball will be 2.6 m/s.

<h3>What is Work energy theorem?</h3>

It states that the Work done in moving a body is equal to the change in kinetic energy of the body

Kinetic energy = 1/2 mv²

Given is a ball of mass m = 0.750 kg and the work done on ball W = 2.50 J

The ball is initially at rest. So, initial velocity is zero. Then, change in kinetic energy will be

W= ΔK.E = K.Ef - K.Ei

According to work energy theorem, work done is

W = 2.5J  = 1/2 x 0.750 x (v)² -0

v =2.6 m/s

Thus, the velocity of the ball is 2.6 m/s

Learn more about work energy theorem.

brainly.com/question/10063455

#SPJ1

6 0
2 years ago
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