A radio technician measures the frequency of an AM radio transmitter. The frequency is . What is the frequency in megahertz? Wri
1 answer:
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The magnitude of velocity for this car is equal to 1.5 m/s.
<u>Given the following data:</u>
- Momentum of car = 3,000 kgm/s.
- Mass of car = 2,000 kg.
To calculate the magnitude of velocity for this car:
<h3>What is momentum?</h3>In Science, momentum simply means a multiplication of the mass of an object and its velocity.
Mathematically, momentum is giving by the formula;
Making velocity the subject of formula, we have:
Substituting the given parameters into the formula, we have;
Velocity = 1.5 m/s.
Read more on momentum here: brainly.com/question/15517471
Answer:
7.55 km/s
Explanation:
The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:
where
is the gravitational constant
is the mass of the telescope
is the mass of the Earth
is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)
v = ? is the orbital velocity of the Hubble telescope
Re-arranging the equation and substituting numbers, we find the orbital velocity:
Answer:
period of oscillations is 0.695 second
Explanation:
given data
mass m = 0.350 kg
spring stretches x = 12 cm = 0.12 m
to find out
period of oscillations
solution
we know here that force
force = k × x .........1
so force = mg = 0.35 (9.8) = 3.43 N
3.43 = k × 0.12
k = 28.58 N/m
so period of oscillations is
period of oscillations = 2π × ................2
put here value
period of oscillations = 2π ×
period of oscillations = 0.6953
so period of oscillations is 0.695 second