In every atom, one or more positive charges are positioned _____

Which of these letters is the symbol for current in equations A: c B: i C: r D: t

True [87]

Answer: [B]: The letter, " I " ; for current; in units of "Amps" .
__________________________________________________

4 0

3 years ago

Two vertical springs have identical spring constants, but one has a ball of mass m hanging from it and the other has a ball of m

OverLord2011 [107]

To solve this problem we will start from the definition of energy of a spring mass system based on the simple harmonic movement. Using the relationship of equality and balance between both systems we will find the relationship of the amplitudes in terms of angular velocities. Using the equivalent expressions of angular velocity we will find the final ratio. This is,

The energy of the system having mass m is,

$E_m = \frac{1}{2} m\omega_1^2A_1^2$

The energy of the system having mass 2m is,

$E_{2m} = \frac{1}{2} (2m)\omega_1^2A_1^2$

For the two expressions mentioned above remember that the variables mean

m = mass

$\omega =$ Angular velocity

A = Amplitude

The energies of the two system are same then,

$E_m = E_{2m}$

$\frac{1}{2} m\omega_1^2A_1^2=\frac{1}{2} (2m)\omega_1^2A_1^2$

$\frac{A_1^2}{A_2^2} = \frac{2\omega_2^2}{\omega_1^2}$

Remember that

$k = m\omega^2 \rightarrow \omega^2 = k/m$

Replacing this value we have then

$\frac{A_1}{A_2} = \sqrt{\frac{2(k/m_2)}{(k/m_1)^2}}$

$\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{m_1}{m_1}}$

But the value of the mass was previously given, then

$\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{m}{2m}}$

$\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{1}{2}}$

$\frac{A_1}{A_2} = 1$

Therefore the ratio of the oscillation amplitudes it is the same.

5 0

3 years ago

A meter 0.0525 m from a wire measures a magnetic field of 7.14 x 10-6 T. How much current flows through the wire?

Harlamova29_29 [7]

Answer:

1.9

Explanation:

5 0

3 years ago

Two air track carts move along an air track towards each other. Cart A has a mass of 450 g and moves toward the right with a spe

ra1l [238]

Answer:

0.465 kgm/s

Explanation:

Given that

Mass of the cart A, m1 = 450 g

Speed of the cart A, v1 = 0.85 m/s

Mass of the cart B, m2 = 300 g

Speed of the cart B, v2 = 1.12 m/s

Now, using the law of conservation of momentum.

It is worthy of note that our cart B is moving in opposite directions to A

m1v1 + m2v2 =

(450 * 0.85) - (300 * 1.12) =

382.5 - 336 =

46.5 gm/s

If we convert to kg, we have

46.5 / 100 = 0.465 kgm/s

Thus, the total momentum of the system is 0.465 kgm/s

6 0

4 years ago

You are standing on perfectly slippery ice. You have a tennis racket and a backpack full of tennis balls, and you propel yoursel

makkiz [27]

Answer:

The distance to the wall does not matter.

Explanation:

According to newton's third law, if you exert a force on the tennis ball to propel it northwards, it will exert equal and opposite force on you to propel you southwards. Therefore, how much you accelerate only depends on how fast you through the balls. And once a ball has left the system ( consisting of you and the ball), it can no longer have an effect on you, so it doesn't matter whether the ball hits a wall nearby or the one millions of miles away.

P.S: all of this is true assuming the balls don't bounce back from the wall and hit you in the face, which would surely give you additional southward acceleration, but it wouldn't be such a pleasant experience!

3 0

4 years ago

In every atom, one or more positive charges are positioned ______.