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Mariulka [41]
3 years ago
6

Which of these letters is the symbol for current in equations A: c B: i C: r D: t

Physics
1 answer:
True [87]3 years ago
4 0
  Answer:  [B]:  The letter, "<em /> I " ; for current;  in units of "Amps" .
__________________________________________________
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When studying atoms, scientists can ignore the blank force
natulia [17]

Answer:

Gravitational Force

Explanation:

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3 years ago
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Two balls of equal size are dropped from the same height from the roof of a building. the mass of ball a is twice that of ball b
Sindrei [870]
The mass of ball a is twice the mass of ball b:
m_a = 2 m_b
This means that the initial potential energy of ball a (U_a = m_a gh=2 m_b gh) is twice the potential energy of ball b (U_b = m_b  g h):
U_a = 2 U_b
When the two balls reach the ground, the potential energy of each ball has converted into kinetic energy (since now their altitude is h=0), because the total mechanical energy of each ball must be  conserved. Therefore:
K_a = U_a
K_b = U_b
and so the kinetic energy of ball a must be twice the kinetic energy of ball b:
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3 years ago
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A large room in a house holds 947 kg of dry air at 33.2°C. A woman opens a window briefly and a cool breeze brings in an additio
BartSMP [9]

Answer:

31.96362 °C

Explanation:

m_1 = Mass of air in the room = 947 kg

m_2 = Mass of air entering the room = 62.4 kg

T_1 = Temperature in the room = 33.2°C

T_2 = Temperature air entering the room = 13.2°C

T = Equilibrium temperature

c = Specific heat of air = 1006 J/kg °C

In the case of thermal equilibrium we have the relation

m_1c(T_1-T)=m_2c(T-T_2)\\\Rightarrow T=\frac{m_2T_2+m_1T_1}{m_1+m_2}\\\Rightarrow T=\frac{62.4(13.2+273.15)+947(33.2+273.15)}{947+62.4}\\\Rightarrow T=305.11362\ K=305.11362-273.15=31.96362^{\circ}C

The temperature of thermal equilibrium is 31.96362 °C

7 0
3 years ago
Short Answer
liq [111]

Answer:

pork, crustaceans, blood, non-halal animal-derived additives such as gelatin or suet, alcohol and any foods containing alcohol as an ingredient

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3 years ago
Evaporation of sweat requires energy and thus take excess heat away from the body. Some of the water that you drink may eventual
kotegsom [21]

Answer:

The amount of heat required is H_t =  1.37 *10^{6} \ J

Explanation:

From the question we are told that

The mass of water is m_w  =  20 \ ounce = 20 * 28.3495 = 5.7 *10^2 g

The temperature of the water before drinking is T_w  =  3.8 ^oC

The temperature of the body is T_b  =  36.6^oC

Generally the amount of heat required to move the water from its former temperature to the body temperature is

H=  m_w  *  c_w * \Delta T

Here c_w is the specific heat of water with value c_w = 4.18 J/g^oC

So

H=   5.7 *10^2 * 4.18 * (36.6 - 3.8)

=> H= 7.8 *10^{4} \  J

Generally the no of mole of sweat present mass of water is

n = \frac{m_w}{Z_s}

Here Z_w is the molar mass of sweat with value

Z_w =  18.015 g/mol

=> n = \frac{5.7 *10^2}{18.015}

=> n = 31.6 \  moles

Generally the heat required to vaporize the number of moles of the sweat is mathematically represented as

H_v  =  n  *  L_v

Here L_v is the latent heat of vaporization with value L_v  = 7 *10^{3} J/mol

=> H_v  =  31.6 * 7 *10^{3}

=> H_v  = 1.29 *10^{6} \  J

Generally the overall amount of heat energy required is

H_t =  H +  H_v

=> H_t =  7.8 *10^{4} +  1.29 *10^{6}

=> H_t =  1.37 *10^{6} \ J

4 0
3 years ago
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