All categories

4 years ago

You bought a freezer that is 2 feet wide, 4 feet long and 30 inches deep. What is the capacity of the freezer?

Physics

2 answers:

erik [133]4 years ago

4 0

Answer:

Volume of freezer, $V=20ft^3$

Explanation:

It is given that,

Length of freezer, l = 4 feet

Width of freezer, b = 2 feet

Depth of freezer, h = 30 inches

Since, 1 inch = 0.0833 feet

So, the depth of freezer, h = 2.5 feet

The capacity of freezer is equal to the volume of freezer and it is given by :

V = lbh

$V=4\times 2\times 2.5$

$V=20ft^3$

So, the capacity if the freezer is 20 cubic feet. Hence, this is the required solution.

Neporo4naja [7]4 years ago

3 0

Capacity of a freezer is actually the volume.
so it will be equal to width*length*depth= 2*4*30= 240 Answer

You might be interested in

A rock is tossed straight up from the ground with a speed of 21 m/s . When it returns, it falls into a hole 10 m deep.a.) What i

Arte-miy333 [17]

(a) 25.2 m/s

Let's take the initial vertical position of the rock as "zero" (reference height).

According to the law of conservation of energy, the speed of the rock as it reaches again the position "zero" after being thrown upwards is equal to the initial speed of the rock, 21 m/s (in fact, if there is no air resistance, no energy can be lost during the motion; and since the kinetic energy depends only on the speed of the rock:

$K=\frac{1}{2}mv^2$

and the gravitational potential energy of the rock has not changed, since the rock has returned into its initial position, it means that the speed of the rock should be the same)

This means that we can only analyze the final part of the motion, the one in which the rock falls into the 10 m hole. Since it is a free fall motion, we can find the final speed by using

$v^2 = u^2 + 2gd$

where

u = 21 m/s is the initial speed of the rock as it enters the hole

g = 9.8 m/s^2 is the acceleration due to gravity

d = 10 m is the depth of the hole

Substituting,

$v=\sqrt{u^2 +2gd}=\sqrt{(21 m/s)^2+2(9.8 m/s^2)(10 m)}=25.2 m/s$

(b) 4.72 s

The vertical position of the rock at time t is given by

$y(t) = v_y t - \frac{1}{2}gt^2$

where

$v_y = 21 m/s$ is the initial vertical velocity

Substituting y(t)=-10 m, we can then solve the equation for t to find the time at which the rock reaches the bottom of the hole:

$-10 = 21 t - \frac{1}{2}(9.8)t^2\\10+21 t -4.9t^2 = 0$

which has two solutions:

t = -0.43 s --> negative, so we discard it

t = 4.72 s --> this is our solution

7 0

4 years ago

A 1,250 kg car is moving due to 6,500 N engine force. If the kinetic friction coefficient between the car and the road is 0.32,

Yuliya22 [10]

Answer:

b i hope this is correct answee

7 0

3 years ago

What is the force exerted on a charge of 2. 5 µC moving perpendicular through a magnetic field of 3. 0 × 102 T with a velocity o

stira [4]

The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.

<h3>What is the force exerted on the charge?</h3>

Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.

when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.

Mathematically the force exerted on the charge will be

F=qvBsinα

F= force acting on the charge

v = velocity of charge

q = charge

F=qvBsinα

F=2.5×10⁻⁶×5.0×10³×3.0×10²

F=37.5 N

Hence The force acting on the charge will be 3.75 N.

To learn more about the force acting on charge refer to ;

brainly.com/question/451411

F = q V B sinα

Where F is the force applied to a moving charge.

V = charge velocity

q stands for charge.

α = angle between V and B directions

As a result, the moving charge is subjected to a force of 3.75 Newton.

3 0

2 years ago

I will mark you as the brainliest if you help and i will give 16 points George created a poster to show the stages of human deve

Mkey [24]

Chidlhood is the answer

4 0

3 years ago

Voltage will be induced in a wire loop when a magnetic field within that loopa. is at right angles to the electric field b. chan

mixas84 [53]

Answer:

changes

Explanation:

According to Michael Faraday, voltage is induced on a metallic conductor when the magnetic field changes. The principle is known as the principle of electromagnetic induction. The voltage induced on the metallic conductor is referred to as induced emf.

The magnitude if induced emf depends on the rate of change of the magnetic flux.

3 0

3 years ago