Answer:
W= 638.1 J
Explanation:
As we know that
Work done is the area of the force and displacement diagram.
W=∫F.dx
W=Work
F=force
dx=Elemental displacement
From the diagram ,area A
A= 60 x 7.09 + 1/2 x 60 x 7.09
A= 638.1 J
So the work W
W= 638.1 J
What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×10^4v ?
Answer:
time is 3333.33 min or 55.55 hr
Explanation:
given data
reactor operating = 1 MW
negative reactivity = $5
power = 1 miliwatt
to find out
how long does it take
solution
we know here power coefficient that is
power coefficient = 
power coefficient = 1
so time required to reach power is
power = reactivity × time / power coefficient + reactor operating
1 ×
= -5 t / 1 + 1 × 
5t =
- 
t = 199999.99 sec
so time is 3333.33 min or 55.55 hr
Answer:
Rs. 432*10^3 (In kilowatts per hour)
I hope it will be useful.
B. sent through the atmosphere