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DaniilM [7]
4 years ago
8

A motorcycle traveling at 15 m/s accelerates at a constant rate of 4.0 m/s over a distance of 50 meters. What is the final veloc

ity of the motorcycle
Physics
1 answer:
ololo11 [35]4 years ago
5 0
From equations of motion,

v^2 = u^2 + 2as ----- v = final velocity, u = initial velocity, a = acceleration, s = distance covered.

Using the vales given;

v^2 = 15^2 + 2*4*50 = 625
v = Sqrt (625) = 25 m/s
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What equation will I need for this problem?
Yuri [45]
The formulas you will need are:

                   Kinetic energy = (1/2) (mass) (speed)² .
and
                   Potential energy = (mass) (gravity) (height) .

And of course,

                   Total energy = constant .
4 0
4 years ago
A tennis player hits a ball at an angle of 50 degrees above horizontal so that it has an acceleration of 12 m/s2. What is the ho
harkovskaia [24]
So we want to know what is the magnitude of the horizontal component of acceleration ah if we know that the overall acceleration a=12 m/s^2 and the angle of overall acceleration and the horizontal acceleration is α=50°. We know that ah=a*cosα. So now it isn't hard to get the horizontal component: ah=12*cos50=12*0.64=7.71 m/s^2. So the correct answer is ah=7.71 m/s^2. 
6 0
4 years ago
Um pls help<br><br>I really need help
Dima020 [189]

Answer:

1.8L

Explanation:

Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship. If volume increases, then pressure decreases and vice versa, when the temperature is held constant.

So x is the volume at pressure 235

235x = 101(4.2)

x = 424.2/235 = 1.8

3 0
3 years ago
a concave mirror forms a real image at 17 cm from the mirror surface along the principal axis. if the corresponding object is at
Step2247 [10]
Image distance (Di) = 17 cm
Object distance (Do) = 36 cm

Using mirror equation,

1/Di + 1/Do = 1/f
1/17 + 1/36 = 1/f
0.058824 + 0.027777 = 1/f
1/f = 0.086601
f= 11.5472 = 11.55 cm
8 0
3 years ago
Calculate the magnetic field at 2m from a straight wire carrying a current of 5 A. (K = 2 x 10 ^-7)
blagie [28]

Answer:

B=5\times 10^{-7}\ T

Explanation:

Given that,

Current in a wire, I = 5 A

We need to find the magnetic field at 2m from a straight wire carrying a current of 5 A.

The magnetic field due to a wire is given by :

B=\dfrac{\mu_0I}{2\pi r}\\\\B=\dfrac{4\pi \times 10^{-7}\times 5}{2\pi \times 2}\\\\B=5\times 10^{-7}\ T

So, the required magnetic field is 5\times 10^{-7}\ T.

6 0
3 years ago
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