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bonufazy [111]
3 years ago
10

A static stretch is ?

Physics
2 answers:
Dafna11 [192]3 years ago
4 0
It is were u hold a potion for a long time
Anna35 [415]3 years ago
3 0
A static stretch is a type of stretch where you hold the position for a long time. 

If this helped please rate, thank, and give brainliest!
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What will be the effect on each of these objects, the bowling ball and the baseball?
Nastasia [14]
What effect man there are a million effects the only one that arent true are fusion or fission and magnetism unless that bowling ball is iron 
7 0
3 years ago
Gamma rays have a higher frequency than visible light waves. What can you conclude from this?
NeTakaya

Answer:

i think it  d

Explanation:

3 0
3 years ago
Read 2 more answers
A rocket is moving away from the solar system at a speed of 7.5 ✕ 103 m/s. It fires its engine, which ejects exhaust with a spee
Elodia [21]

Answer:

a.2.5x 10^3 m/s

b.mr=48kg/s

Explanation:

A rocket is moving away from the solar system at a speed of 7.5 ✕ 103 m/s. It fires its engine, which ejects exhaust with a speed of 5.0 ✕ 103 m/s relative to the rocket. The mass of the rocket at this time is 6.0 ✕ 104 kg, and its acceleration is 4.0 m/s2. What is the velocity of the exhaust relative to the solar system? (B) At what rate was the exhaust ejected during the firing?

velocity of the exhaust relative to the solar system

velocity of the rocket -velocity of the exhaust relative to the rocket.

7.5 ✕ 103 m/s-5.0 ✕ 103 m/s

2.5x 10^3 m/s

. b  we will look for the thrust of the rocket

T=ma

T=6.0 ✕ 104 kg*4.0 m/s2

T=2.4*10^5N

f=mass rate *velocity of the exhaust

T=2.4*10^5N=mr*5.0 ✕ 10^3 m/s

mr=2.4*10^5N/5.0 ✕ 10^3

mr=48kg/s

5 0
2 years ago
Estimate the speed of the water free surface and the time required to fill with water a cone-shaped container 1.5 m high and 1.5
Zolol [24]

Answer:

speed of water is 0.0007138m/s

Explanation:

From the law of conservation of mass

Rate of mass accumulation inside vessel = mass flow in - mass flow out

so, dm/dt = mass flow in - mass flow out

taking p as density

d \frac{dQ}{dt} = pq_i_n

where,

q(in) is the volume flow rate coming in

Q = is the volume of liquid inside tank at any time

But,

dQ = Adh

where ,

A = area of liquid surface at time t

h = height from bottom at time t

A = πr²

r is the radius of liquid surface

r = (1.5/2) \div 1.5 h = \frac{h}{2}

Hence,

\pi( \frac{h}{2} )^2\frac{dh}{dt} =q_i_n

\frac{dh}{dt} = \frac{q_i_n}{\pi (\frac{h}{2})^2 } =\frac{4q_i_n}{\pi h^2}

so, the speed of water surface at height h

v = \frac{dh}{dt} =\frac{4q_i_n}{\pi h^2}

where,

q_i_n is 75.7 L/min = 0.0757m³/min

h = 1.5m

so,

v = \frac{4 \times 0.0757}{\pi \times 1.5^2} \\\\v = 0.04283m/min

v = 0.04283 /60

v = 0.0007138m/s

Hence, speed of water is 0.0007138m/s

5 0
3 years ago
A lead mass is heated and placed in a foam cup calorimeter containing 50.0 ml of water at 18.0°c. the water reaches a temperatur
maria [59]
Assuming that there is no heat loss, and the cup is perfectly insulated, all of the energy lost by the lead will be absorbed by the water.
The heat absorbed is given by:
Energy = mass * specific heat capacity * change in temperature
The specific heat capacity of water is 4.18 joules per gram.

In order to compute the mass, we will use the fact that the density of water is one gram per milliliter. Therefore, the mass of water is 50 grams.

Now,
Q = 50 * 4.18 * (20 - 18)
Q = 418 J

418 Joules of energy were released by the lead.
4 0
3 years ago
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