Two objects of equal mass are a distance of 5.0 m apart and attract each other with a gravitational force of 3.0 x 10^-7 N find
1 answer:
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Answer:
Force constant will be 1195.85 N/m
Work done will be 1.6859 J
Explanation:
We have given the force, F = 63.5 N
Spring is stretched by 5.31 cm
So x = 0.0531 m
Force is given , F = 63.5 N
We know that force is given by
So
k = 1195.85 N/m
Now we have to find the work done
We know that work done is given by
1) The distance travelled by the electron is
2) The time taken is
Explanation:
1)
The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance travelled
For the electron in this problem,
is the initial velocity
v = 0 is the final velocity (it comes to a stop)
is the acceleration
Solving for s, we find the distance travelled:
2)
The total time taken for the electron in its motion can also be found by using another suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
Here we have
v = 0
And solving for t, we find the time taken:
Learn more about accelerated motion:
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Answer:
A. 0.199 J
B. 0.0663 C
C = 0.0221 F
D. 12.68 ohms
Explanation:
From the question:
time duration, t = 0.28 seconds
Average power, P = 0.71 W
Average voltage, V = 3 V
A) Energy is given as:
E = P * t
=> E = 0.71 * 0.28 = 0.199 J
B) Electrical energy is also given as:
E = qV
where q = charge
=> q = E / V
∴ q = 0.199 / 3 = 0.0663 C
C) Capacitance is given as charge over voltage:
C = q / V
=> C = 0.0663 / 3 = 0.0221 F
D) Electrical power, P, can also be given as:
P =
where R = resistance
=> R =
R =