1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mafiozo [28]
3 years ago
6

A 1750-kilogram cars travels at a constant speed of 15.0 meters per second around a horizontal, circular track with a radius of

45.0 meters. The magnitude of the centripetal force acting on the car is
Physics
1 answer:
bulgar [2K]3 years ago
6 0

m = mass of the car moving in horizontal circle = 1750 kg

v = Constant speed of the car moving in the horizontal circle = 15 m/s

r = radius of the horizontal circular track traced by the car = 45.0 m

F = magnitude of the centripetal force acting on the car

To move in a circle . centripetal force is required which is given as

F = m v²/r

inserting the above values in the formula

F = (1750) (15)²/(45)

F = (1750) (225)/(45)

F = 1750 x 5

F = 8750 N

You might be interested in
What are dimensionless quantities??​
bearhunter [10]

Answer:

Characteristic numbers are dimensionless numbers used in fluid dynamics to describe a character of the flow. To compare a real situation with a small-scale model it is necessary to keep the important characteristic numbers the same. Names of these numbers were standardized in ISO 31, part 12.

Explanation:

7 0
3 years ago
Pls help me with this​
OLEGan [10]

Answer:

I can't see it because it's too blury. try to search it

7 0
3 years ago
Hàng ngày ta thấy Mặt trời , Mặt trăng quay quanh Trái Đất, khi đó ta đã lấy vật mốc là
marshall27 [118]
I’m sorry I don’t understand this language
5 0
3 years ago
Which of the following causes current to flow in a wire?
SVEN [57.7K]
The answer should be B
7 0
3 years ago
Read 2 more answers
A ball thrown straight upwards with an initial velocity of 15 m/s. Calculate how long the ball will remain in the air and the ma
GenaCL600 [577]

Answer:

The ball remain in air for 3.06 seconds.

Maximum height reached = 22.94 m

Explanation:

We have equation of motion v = u + at

At maximum height, final velocity, v =0 m/s

       Initial velocity = 15 m/s

       acceleration = -9.81 m/s²

Substituting

       0 = 15 -9.81 t

        t = 1.53 s

Time of flight = 2 x 1.53 = 3.06 s

The ball remain in air for 3.06 seconds.

We also have equation of motion v² = u² + 2as

At maximum height, final velocity, v =0 m/s

       Initial velocity = 15 m/s

       acceleration = -9.81 m/s²

Substituting

       0² = 15² - 2 x 9.81 x s

        s = 22.94 m

Maximum height reached = 22.94 m

3 0
3 years ago
Other questions:
  • About three billion years ago, single-celled organisms called cyanobacteria lived in Earth’s oceans. They thrived on the ocean’s
    12·2 answers
  • Procedure on making electricity using solar
    14·1 answer
  • Two forces that are not equal in size are
    15·1 answer
  • I only need the answer to #21
    6·1 answer
  • Which scientist discovered the realtionship between electricity and magnetism​
    5·1 answer
  • A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.2 m/s. The drag force is of the form bv2 What is the value of b?
    8·1 answer
  • A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.
    9·1 answer
  • 1. Compare pressure that fluid applies to the bottom of a glass with the pressure it applies to the sides of the glass
    9·1 answer
  • Rewire each of the following using the correct prefix using 2 decimal places where applicable.
    8·1 answer
  • I need help ASAP please :)
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!