Answer:
c line of credit I believe
Answer: a) Mr = 2.4×10^-4kg/s
V = 34.42m/a
b) E = 173J
Ø = 2693.1J
c) Er = 0.64J/s
Explanation: Please find the attached file for the solution
Answer:
The mass of the banana is m and it is at height h.
Applying the Law of Conservation of Energy
Total Energy before fall = Total Energy after fall
=
Here, total energy is the sum of kinetic energy and potential energy
+
=
+
(a)
When banana is at height h, it has
= 0 and
= mgh
and when it reaches the river, it has
= 1/2m
and
= 0
Putting the values in equation (a)
0 + mgh = 1/2m
+ 0
mgh = 1/2m![v^{2}](https://tex.z-dn.net/?f=v%5E%7B2%7D%20)
<em>cutting 'm' from both sides</em>
<em> </em>gh = 1/2![v^{2}](https://tex.z-dn.net/?f=v%5E%7B2%7D%20)
v = ![\sqrt{2gh}](https://tex.z-dn.net/?f=%5Csqrt%7B2gh%7D%20)
Hence, the velocity of banana before hitting the water is
v = ![\sqrt{2gh}](https://tex.z-dn.net/?f=%5Csqrt%7B2gh%7D%20)
Organisms, organs, tissues, cell ....
a more specific answer would be:
organism, organ system, organ, tissue, cell, atom
Velocity increases with speed