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EleoNora [17]
3 years ago
14

PJ’s unknown solid 1) dissolves in hot ethanol, 2) is essentially insoluble in hexane, and 3) is insoluble in cold water, but sp

aringly soluble in warm water. Outline the recrystallization procedure you would suggest she use here.
Chemistry
1 answer:
Gnoma [55]3 years ago
5 0

Answer:

1. The solid is dissolved in the hot solvent (ethanol or water);

2. If the impurities are not dissolved, they are separated by filtration;

3. The solution is then cold, and the crystals of the solid are formed;

4. The solution is filtrated and the pure solid is obtained.

Explanation:

The recrystallization is a process to separate impurities from a solid. The solid with the impurities is dissolved in a hot solvent, and, is insoluble in the cold one. But the impurities must be soluble in the cold solvent, or insoluble in the hot one.

If the impurities are soluble in the cold solvent, then, the crystals of the analyte will be removed, and if they are insoluble in the hot solvent, then its crystal is removed first.

So let's assume that the solid is insoluble in hot ethanol, and soluble in hot water. Because its insoluble in hexane, the recrystallization is not possible with it. So the procedure would be:

1. The solid is dissolved in the hot solvent (ethanol or water);

2. If the impurities are not dissolved, they are separated by filtration;

3. The solution is then cold, and the crystals of the solid are formed;

4. The solution is filtrated and the pure solid is obtained.

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The answer for this selection is 4

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3 years ago
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Answer :

A car stopped at the top of a hill

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3 years ago
Which of the fallowing elements is the most reactive?
Alexxx [7]
Which elements are most reactive?

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4 years ago
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Semmy [17]

Reactions like this one absorb energy because the reactants have less potential energy than the products.

<h3>What is an Endothermic reaction?</h3>

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8 0
2 years ago
The Ksp of yttrium iodate, Y(IO3)3 , is 1.12×10−10 . Calculate the molar solubility, s , of this compound.
torisob [31]

Answer:

1.427x10^-3mol per L

Explanation:

Y(IO_{3} )_{3} ---- Y^{3+} +IO_{3} ^{3-}

I could use ⇌ in the math editor so I used ----

from the question each mole of Y(IO3)3 is dissolved  and this is giving us a mole of Y3+ and a mole of IO3^3-

Ksp = [Y^3+][IO3-]^3

So that,

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so in conclusion

the molar solubility is therefore 1.427x10^-3mol per L

3 0
3 years ago
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