A plane parallel to vectors <9, 6, 2> and <-8, -4, -5> is given by

Since the plane passes through point (5, -5, 8), then
-22(5) + 29(-5) + 12(8) = -110 - 145 + 96 = -159
The required plane is -22x + 29y + 12z = -159
z = 11/6x - 29/12y - 53/4
Answer:
(-1,-1)
Step-by-step explanation:
down 2 affects the y, so 1-2=-1
Left 4 affects the x, so 3-4=-1
You have forgotten to add the figure, so unfortunately, no one can help you right now.
Answer:

Step-by-step explanation:
We have given differential equation 
We know that linear differential equation is given by 
On comparing with standard equation P = -2 and Q= 
Now integrating factor 

Now solution of differential equation is given by




The answer is - 40. Observe.
y/-4 + 5 = 15
y = -40
-40/-4 = 10
10 + 5 = 15
Thus, y= -40