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kondaur [170]
3 years ago
12

HHEELLPP ME GET A GOOD GRADE

Mathematics
1 answer:
muminat3 years ago
6 0
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
A(\stackrel{x_1}{2m}~,~\stackrel{y_1}{2n})\qquad 
C(\stackrel{x_2}{2p}~,~\stackrel{y_2}{2r})
\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}~~~ ,~~~ \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{2p+2m}{2}~~,~~\cfrac{2r+2n}{2} \right)\implies \left( \cfrac{\underline{2}(p+m)}{\underline{2}}~~,~~\cfrac{\underline{2}(r+n)}{\underline{2}} \right)
\\\\\\
~~~~~~~~[(p+m)~,~(r+n)]
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Below is the graph of a trigonometric function. It has a minimum point at (2, -0.9) and an amplitude of 3.
Anestetic [448]

Answer: it’s 2.1

Step-by-step explanation:

Amplitude + y value 3+-0.9=2.1

Your welcome :)

3 0
3 years ago
Can someone explain this?
natulia [17]

Answer:

58 degrees

Step-by-step explanation:

(x+45)+(x+66)=95

2x+45+66=95

2x+111=95

2x=95-111

2x=-16

x=-16/2

x=-8

x+66=-8+66=58

8 0
3 years ago
Read 2 more answers
(Angles) Only 14-17 please, do 15 if you want
Butoxors [25]

Answer:

N.14 ABC = 5x+20, N.15 ABE = 90. N.16. 123, 29, 28. N.17 K = 80

Step-by-step explanation:

Because of vertical angles, 5x+20 = 3x+66.

5x=3x+46

2x = 46

x = 23

Sum of angles in a circle is 360

360-135-135=180

ABE = CBD because vertical angles.

180 / 2 = 90

16.

Sum of angles in triangle is 180

180=123-x-2-x-3

x = 31

123, 29, 28.

17.

Sum of angles in triangle is 180

180-72-28 = 80

K = 80

8 0
2 years ago
A triangular prism has a base area of 20 square feet and a height of 4 feet. Find the volume.
GaryK [48]
80 is the answer i hope i helped g
5 0
3 years ago
A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 in. What are
Lesechka [4]

Answer:

a) \frac{28}{\pi} in

b) 28 in

c) 784 in²

Step-by-step explanation:

Let the length be 'L'

and the radius be 'r'

Thus, according to the question

L + 2πr = 84 in

L = 84 - 2πr   ............(1)

Volume of the cylinder, V = πr²L

substituting the value of L from 1, we get

V =  πr²(84 - 2πr)

or

V = 84πr² - 2π²r³

for points of maxima, differentiating the above equation and equating it to zero

\frac{dV}{dr}=\frac{d(84\pi r^2-2\pi^2 r^3))}{dr}

or

2(84)πr - 3(2)π²r² = 0

or

2πr(84 - 3πr) = 0

or

r = 0    and    84 - 3πr = 0

or

⇒ 3πr = 84

or

⇒ r = \frac{28}{\pi} in

since, the radius cannot be zero therefore, r = 0 is neglected

Therefore,

a) The radius of the largest cylindrical package = \frac{28}{\pi} in

b) from  (2)

L = 84 - 2πr

or

⇒ L = 84 - 2\pi\times\frac{28}{\pi}

or

⇒ L = 84 - 56 = 28 in

The length of the largest cylindrical package = 28 in

c ) The volume of the largest cylindrical package ,V = πr²L

= \pi\times\frac{28}{\pi}\times28

= 784 in²

7 0
3 years ago
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