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3 years ago

Escriba las fórmulas semi desarrollada y global correspondientes a: 2,3-dimetil-1-penteno

Chemistry

1 answer:

hammer [34]3 years ago

7 0

Answer:

En la imagen adjunta.

Explanation:

Hola.

En este caso, debemos recordar que la fórmula semi desarrollada se relaciona con la fórmula estructural del compuesto orgánico a representar; de este modo, primeramente encontramos una cadena de cinco carbonos con un doble enlace en el primer carbono y dos radicales metil tanto en el segundo como en el tercer carbono. Por otro lado, la formula global muestra el tipo y número de átomos presentes en el compuesto, que para el dado, son siete átomos de carbono y catorce de oxígeno, según se puede observar en la imagen adjunta.

¡Saludos!

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Answer: Option (a) is the correct answer.

Explanation:

Atomic number is the sum of only total number of protons present in an element. Whereas mass number is the sum of total number of both protons and neutrons present in an element.

For example, given atom has mass number as 15 and its atomic number is 7.

Therefore, number of neutrons present in it will be calculated as follows.

Mass number = no. of protons + no. of neutrons

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no. of neutrons = 15 - 7

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Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

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The expression for enthalpy change is,

$\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]$

Putting the values we get :

$\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]$

$\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]$

$\Delta H=-5314.8kJ$

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = $\frac{5314.8}{2}\times 1=2657.4kJ$

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

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