Answer:
The structure with the ring flipped is the most stable
Explanation:
We have the trans 1,2 - dimethylcyclohexane. With the wedge/dash structure we could not figure is this form is stable (If we do a comparison with the cis structure). But when we do a chair structure and ring flipped structure, this is easier to look.
The picture attached shows the structures, they are labeled as 1, 2 and 3, according to this problem.
In the chair structure, according to the picture below, you can see that both methyls are heading in the axial positions of the ring (One facing upward and the other downward). This is pretty stable, however, when the methyls are in those positions, the methyl position 1, can undergoes an 1,3 diaxial interactions with the hydrogens atoms (They are not drawn, but still are there), so this interaction makes this structure a little less stable that it can be.
On the other side, the ring flipped structure, we can see that both methyls are in the equatorials positions of the ring, and in these positions, it can avoid the 1,4 diaxial interactions with the hydrogens atoms, making this structure the most stable structure.
Hope this helps
<h2>b is the correct answer</h2>
according In my course I studying it all
Answer:
The intermolecular forces between the solute and solvent.
Explanation:
When you are heating a solvent, the intermolecular forces are reduced because the distances between molecules are large. Thus, in a solution where solvent is hot the intermolecular forces between solute and solvent are lower than those solutions where solvent is in room temperature.
The covalent bonds do not change because this mean a chemical reaction that doesn't occur in a solution.
Usually solid solutes melts in a higher temperature than boiling point in solvents. Thus, a compound normally doesn't melt in a hot solvent.
I hope it helps!
Answer:
If an insufficient amount of nitrogen were produced, the air bag would under inflate and not provide adequate protection. Clearly, the stoichiometry of the reaction is very important.
Answer:
1. Add N2O and
3. Remove N2
Explanation:
In equilibrium, there is a balance between the concentrations of the reactants and products. If more reactants are added, the equilibrium will shift to the right, favoring the forward reaction. This cause an increase in the concentration of the product and the equilibrium constant is unchanged.
Products can also be removed in order to increase the amount of products formed, forward reaction. This shifts the equilibrium to the right.
In the reaction 2N2O <-----> O2 + 2N2, adding N2O to the mixture favors the forward reaction and more products are formed, equilibrium shifts to the right.
Also, removing the product formed favors the forward reaction as more products will be formed in order to achieve equilibrium. The equilibrium therefore shifts to the right.
