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Elina [12.6K]
3 years ago
10

Find the quotient of 2.632 x 10^4 and 2 x 10^-7

Mathematics
1 answer:
givi [52]3 years ago
6 0
(2.632\cdot10^4):(2\cdot10^{-7})=(2.632:2)\cdot(10^4:10^{-7})\\\\=1.316\cdot10^{4-(-7)}=1.316\cdot10^{4+7}=\boxed{1.316\cdot10^{11}}
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pshichka [43]

Length of the rectangle is 51 inches

<u>Solution:</u>

Given that

Length of the rectangle in 34 miles less than 5 times its width

Area of rectangle = 867 square inches

Need to determine length of the rectangle.

Let assume width of the rectangle be represented by variable x.

So 5 times width of the rectangle =5x

34 inches less than 5 times width of the rectangle = 5x – 34

As Length of the rectangle in 34 miles less than 5 times its width

=> Length of the rectangle = 5x – 34

<em><u>The formula for rectangle is given as:</u></em>

\text { area of rectangle }=length \times width

As given that Area of rectangle = 867 square inches

\begin{array}{l}{=>867=(5 x-34) \times(x)} \\\\ {=>5 x^{2}-34 x-867=0}\end{array}

On solving quadratic equation by using quadratic formula

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case a = 5, b = -34 and c = -867

On substituting value of a, b and c in quadratic formula we get

\begin{array}{l}{x=\frac{-(-34) \pm \sqrt{(-34)^{2}-4 \times 5 \times(-867)}}{2 \times 5}} \\\\ {=>x=\frac{34 \pm \sqrt{18496}}{10}=\frac{34+136}{10}} \\\\ {=>x=\frac{34+136}{10}=17 \text { or } x=\frac{34-136}{10}=-10.2}\end{array}

Since x represents width, it cannot be negative, so x = 17

Length of the rectangle = 5x – 34 = 5(17) – 34 = 51

Hence length of the rectangle is 51 inches

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3 years ago
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Hello!

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Answer:

12 years

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