Answer:
m = T/10 = (1/10) T
Explanation:
From the question given:
∑F = ma .... (1)
∑F = T – 10m .... (2)
a = 0 m/s²
m =?
Thus, we can obtain m in terms of T as shown below:
From equation (1)
∑F = ma
a = 0 m/s²
∑F = ma = m × 0
∑F = 0
Next, substitute the value of ∑F into equation (2) to obtain m. This is illustrated below:
∑F = T – 10m
∑F = 0
0 = T – 10m
Rearrange
0 + 10m = T
10m = T
Divide both side by 10
m = T/10
m = (1/10) T
Therefore, m is (1/10) T
Answer:
A) Rapidez
Explanation:
Speed is a scalar quantity and it is found by dividing the distance traveled by the time taken.
Speed =
Distance is the length of path covered whereas time is the duration of the travel.
Unlike velocity which is a vector, speed is a scalar quantity with only magnitude but no direction.
F=ma
Force=mass*acceleration
So plug in the values
Hint: the force would be measured in newtons
The work done by
along the given path <em>C</em> from <em>A</em> to <em>B</em> is given by the line integral,

I assume the path itself is a line segment, which can be parameterized by

with 0 ≤ <em>t</em> ≤ 1. Then the work performed by <em>F</em> along <em>C</em> is
![\displaystyle \int_0^1 \left(6x(t)^3\,\vec\imath-4y(t)\,\vec\jmath\right)\cdot\frac{\mathrm d}{\mathrm dt}\left[x(t)\,\vec\imath + y(t)\,\vec\jmath\right]\,\mathrm dt \\\\ = \int_0^1 (288(3t-1)^3-8(2t+5)) \,\mathrm dt = \boxed{312}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E1%20%5Cleft%286x%28t%29%5E3%5C%2C%5Cvec%5Cimath-4y%28t%29%5C%2C%5Cvec%5Cjmath%5Cright%29%5Ccdot%5Cfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Bx%28t%29%5C%2C%5Cvec%5Cimath%20%2B%20y%28t%29%5C%2C%5Cvec%5Cjmath%5Cright%5D%5C%2C%5Cmathrm%20dt%20%5C%5C%5C%5C%20%3D%20%5Cint_0%5E1%20%28288%283t-1%29%5E3-8%282t%2B5%29%29%20%5C%2C%5Cmathrm%20dt%20%3D%20%5Cboxed%7B312%7D)