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goldfiish [28.3K]
3 years ago
12

Why is the sky blue? The earth is surrounded by an atmosphere.

Physics
1 answer:
madreJ [45]3 years ago
3 0

Answer:

The blue component of the spectrum of visible light has shorter wavelengths and higher frequencies than the red component. Thus, as sunlight of all colors passes through air, the blue part causes charged particles to oscillate faster than does the red part. The faster the oscillation, the more scattered light is produced, so blue is scattered more strongly than red. For particles such as air molecules that are much smaller than the wavelengths of visible light the difference is dramatic. The acceleration of the charged particles is proportional to the square of the frequency, and the intensity of scattered light is proportional to the square of this acceleration. Scattered light intensity is therefore proportional to the fourth power of frequency. The result is that blue light is scattered into other directions almost 10 times as efficiently as red light.

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A box with a weight of 100 N rests on a horizontal floor. The coefficient of static friction is = 0,40 and the coefficient of ki
kompoz [17]
Weight=100N
SF=0.4
KF=0.3
Magnitude?
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7 0
2 years ago
A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its
Nostrana [21]

Answer:

Its speed is maximum and its acceleration is zero

Explanation:

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In a simple harmonic motion, the speed can be determined through the law of conservation of energy. In fact, we have that the total mechanical energy of the system, which is sum of elastic potential energy U and kinetic energy K, is constant:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2

where k is the spring constant, x is the displacement, m is the mass and v is the speed.

We see that when the displacement is 0, x = 0: this means that the elastic potential energy U is also 0, therefore the kinetic energy K is maximum, and so the speed v is also maximum.

- Concerning the acceleration:

According to Newton's second law, the acceleration of the system is proportional to the net force:

a=\frac{F}{m}

the net force is just the restoring force of the spring, given by Hooke's law:

F=-kx

So, the acceleration is

a=-\frac{kx}{m}

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4 0
4 years ago
Find an expression for the electric field e⃗ at the center of the semicircle. hint: a small piece of arc length δs spans a small
ahrayia [7]
Let l = Q/L = linear charge density. The semi-circle has a length L which is half the circumference of the circle. So w can relate the radius of the circle to L by 

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<span>dq = l*ds = l*R*da </span>

<span>So the electric field can be written as: </span>

<span>dE =kdq*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>

<span>dE = k*I*R*da*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>

<span>E = k*I*(sin(a)/R I_hat - cos(a)/R^2 j_hat) </span>

<span>E = pi*k*Q/L(sin(a)/L I_hat - cos(a)/L j_hat)</span>
8 0
3 years ago
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Nataly [62]

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8 0
3 years ago
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