What is the equilibrium expression for the reatcion bellow<br><br> 2SO3(g)<=>O2(g)+2SO2(g)

Hydrophobic molecules (like oil) tend to self-associate in water rather than dissolve. What is the MAJOR energetic contribution

anyanavicka [17]

Answer: The MAJOR energetic contribution to this property is the self association that maximizes the entropy of the water molecules.

Explanation:

Hydrophobic molecules (like oil) tend to self-associate in water rather than dissolve in it. The MAJOR energetic contribution to this property is the self association of this oil which increases the degree of disorderliness of the water molecules.

4 0

3 years ago

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What is the specific latent heat of a fussion for a substance that takes 550 kj to melt 14 kg at 262 k?

Lina20 [59]

The latent heat is correlated with energy as follows:

Q = mL

550 * 103 = 14 * 103 * L

L = 39.285 J /g

Thus, latent heat of the substance is 39.285 j /g

7 0

3 years ago

Which tool is used to measure an object's mass

natka813 [3]

Answer:

A scale, or a weight. Both of which are more scientifically referred to as a balance.

3 0

3 years ago

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Explain what it means to be considered a “renewable” energy source, and what it means to be a “non-renewable” energy source.

Neporo4naja [7]

Answer: Resources are characterized as renewable or nonrenewable

- a renewable resource can replenish itself at the rate it is used such as solar energy, wind energy, hydro energy, and tidal energy.

- a nonrenewable resource has a limited supply such as coal, gas, nuclear energy, and fossil fuels.

3 0

3 years ago

New questionWhat mass of calcium chloride (CaCl₂) would beproduced from the reaction of 125.9 g of hydrochloriacid (HCI) with ex

marshall27 [118]

Answer:

191.6 g of CaCl₂.

Explanation:

What is given?

Mass of HCl = 125.9 g.

Molar mass of CaCl₂ = 110.8 g/mol.

Molar mass of HCl = 36.4 g/mol.

Step-by-step solution:

First, we have to state the chemical equation. Ca(OH)₂ react with HCl to produce CaCl₂:

$Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O.$

Now, let's convert 125.9 g of HCl to moles using the given molar mass (remember that the molar mass of a compound can be found using the periodic table). The conversion will look like this:

$125.9\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=3.459\text{ moles HCl.}$

Let's find how many moles of CaCl₂ are being produced by 3.459 moles of HCl. You can see in the chemical equation that 2 moles of HCl reacted with excess Ca(OH)₂ produces 1 mol of CaCl₂, so we state a rule of three and the calculation is:

$3.459\text{ moles HCl}\cdot\frac{1\text{ mol CaCl}_2}{2\text{ moles HCl}}=1.729\text{ moles CaCl}_2.$

The final step is to find the mass of CaCl₂ using the molar mass of CaCl₂. This conversion will look like this:

$1.729\text{ moles CaCl}_2\cdot\frac{110.8\text{ g CaCl}_2}{1\text{ mol CaCl}_2}=191.6\text{ g CaCl}_2.$

The answer would be that we're producing a mass of 191.6 g of CaCl₂.

4 0

1 year ago

What is the equilibrium expression for the reatcion bellow 2SO3(g)<=>O2(g)+2SO2(g)