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allochka39001 [22]
4 years ago
8

What is the equilibrium expression for the reatcion bellow 2SO3(g)<=>O2(g)+2SO2(g)

Chemistry
1 answer:
Luda [366]4 years ago
8 0

Answer:

[O2(g)][SO2(g)]^2/[SO3(g)]^2

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4NaCl + 2SO2 + _____H2O + _____O2 → _____Na2SO4 + 4HCl
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The numbers that balance the following equation: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl is 2, 1, 2.

BALANCING EQUATION:

  • Balancing a chemical equation means to make sure that the number of atoms of each element on both sides of the equation are equal.

  • According to this question, the following chemical reaction are given: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl

  • Some of the coefficients (numbers) have been placed there while some are missing. The equation that includes the missing coefficients (numbers) to balance the equation is:

4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl

Learn more at: brainly.com/question/21049751?referrer=searchResults

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When nitrogen gas (N2) reacts with hydrogen gas(H) ammonia gas (NH3) is formed. How many grams of hydrogen gas are required to r
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Mass of Hydrogen gas required to react : 0.936 g

<h3>Further explanation</h3>

Reaction on Nitrogen gas and Hydrogen gas to produce Ammonia gas

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Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol

so mol Nitrogen for 3.5 L at STP :

\tt mol=\dfrac{3.5~L}{22.4~L}=0.156

From the equation, mol ratio of N₂ : H₂ = 1 : 3, so mol H₂ :

\tt \dfrac{3}{1}\times 0.156=0.468

then mass of Hydrogen(MW= 2 g/mol) :

\tt mass=mol\times MW\\\\mass=0.468\times 2\\\\mass=0.936~g

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