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allochka39001 [22]
3 years ago
8

What is the equilibrium expression for the reatcion bellow 2SO3(g)<=>O2(g)+2SO2(g)

Chemistry
1 answer:
Luda [366]3 years ago
8 0

Answer:

[O2(g)][SO2(g)]^2/[SO3(g)]^2

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How does amount of greenhouse gases affect the temperature of the Earth's atmosphere?
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greenhouse gases can cause Earth's atmosphere to trap more and more heat. This causes Earth to warm up.

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A wooden plank has a mass of 100kg force of 20 n was used to move it what is its acceleration​
krok68 [10]

Answer:

a= 0.2m/s²

Explanation:

Fnet = ma

20 = 100a (divide both sides by 100)

a = 0.2m/s²

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5. Name five plants and animals that lived in ancient Antarctica
Andrew [12]

Answer:

Two hundred million years ago, Antarctica was a lush, temperate rainforest home to crocodile-sized amphibians and rhinoceros-sized dinosaurs.

Explanation:

Animals:

1 ankylosaurs (the armored dinosaurs), mosasaurs and plesiosaurs (both marine reptilian groups).

2 Cry-oloph-os-auru-s was the ap-ex pre-da-tor of its region when it hunted in the lands of Jur-as-sic Period Antarctica.

3 plesiosaurs.

4 mosasaurs.

Plants:

1 palm trees.

2 ferns and Tanglefoot.

3 Evergreen trees

4 Glossopteris

8 0
2 years ago
If you can smell your grandmother’s perfume from across the room, you are experiencing the result of which liquid property?
cestrela7 [59]
The appropriate answer is D. volatility. Volatility refers to the susceptibility of liquids to vaporize. Perfume is liquid when applied but because of volatility, it has a tendency to vaporize and so it will convert to a gas and diffuse across the room. The process by which a liquid changes to a vapor is called evaporation. 
5 0
3 years ago
How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with
konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = a=31 cm^2

Thickness of the gold plating  = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3

Density of the gold = d=19.3 g/cm^3

m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g

Moles of gold = \frac{29.915 g}{197 g/mol}=0.152 mol

Au^{3+}+3e^-\rightarrow Au

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

\frac{3}{1}\times 0.152 mol=0.456 mol of electrons

Number of electrons = N =0.456\times \times 6.022\times 10^{23}

Charge on single electron = q=1.6\times 10^{-19} C

Total charge required = Q

Q=N\times q

Amount of current passes = I = 8 Ampere

Duration of time  = T

I=\frac{Q}{T}

T=\frac{N\times q}{I}

=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0
3 years ago
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