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anastassius [24]
2 years ago
6

100 POINTS AND BRAINLIEST

Chemistry
2 answers:
baherus [9]2 years ago
7 0

Answer:

please brainliest

Explanation:

the equation formula answer is x^{2} fxb\sqrt{3

harina [27]2 years ago
4 0
Whatever the person said above is the answer
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determine mass of water formed when 12.5 L NH3(at298K and 1.50atm) is reacted with 18.9L of O2 (at 323K and 1.1atm)
sasho [114]

The  mass  of water formed  is


<u><em>calculation</em></u>

Use  the  ideal   gas  equation   to  calculate the  moles of  NH3  and O2

that  is  Pv= n RT

where;  P= pressure,  

V=  volume,

n = number  of  moles,

R=gas   constant  = 0.0821  l .atm/ mol.K

make n the formula of  the subject  by diving   both side  by  RT

n =  PV /RT

The   moles of NH3

n= (1.50 atm  x 12.5 L) /(  0.0821 L. atm /mol.k   x 298 K)  =0.766  moles

The  moles  of  O2

=(1.1 atm  x 18.9  L) /  (  0.0821 L. atm/ mol.k   x 323 K) = 0.784  moles


write the reaction  between  NH3  and  O2

4 NH3  + 5 O2  →4 No  +6H2O


from  equation above  0.766  moles of NH3  reacted to produce  

0.766 x 6/4 =1.149 moles of H2O


0.784  moles of O2   reacted to  produce  0.784  x 6/5=0.9408  moles  of H20


since  O2  is totally  consumed, O2  is the limiting  reagent  and therefore  the  moles of H2O  produced=  0.9408  moles


mass  of  H2O  = moles x molar mass

 from  periodic table the  molar mass  of H2O  =  (1 x2)+16= 18  g/mol

mass = 18 g/mol  x 0.9408  moles= 16.93  grams


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An evil villain wants to broadcast a message to everyone on Earth. They are using satellites for the communication process. For
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What happens if a geologist drips a small amount of vinegar (acetic acid) onto a sample of dolomite?
Lapatulllka [165]
Hydrochloric acid on a rock or mineral and watching for bubbles of carbon dioxide gas to be released. The bubbles signal the presence of carbonate minerals such as calcite and dolomite.
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HELP!!!! ASAP!!!!!!!!!!<br><br> HOW ARE REACTANTS DIFFERENT FROM THE PRODUCTS ?
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Reactants are what make up the product.
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An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The ballo
Liula [17]

The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

Answer : The new volume of the balloon is 25.7 L

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1 = initial volume of gas = 27.8 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 13^oC=273+13=286K

T_2 = final temperature of gas = -9^oC=273+(-9)=264K

Now put all the given values in the above equation, we get:

\frac{27.8L}{286K}=\frac{V_2}{264K}

V_2=25.7L

Therefore, the new volume of the balloon is 25.7 L

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2 years ago
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