Answer:
1.36x10^10L
Explanation:
Step 1:
Determination of the mole of fluorine that contains 3.66x10^32 molecules. This is shown below:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This implies that 1 mole of fluorine also contains 6.02x10^23 molecules.
Now if 1 mole of fluorine contains 6.02x10^23 molecules,
Therefore, Xmol of fluorine will contain 3.66x10^32 molecules i.e
Xmol of fluorine = 3.66x10^32/6.02x10^23
Xmol of fluorine = 6.08x10^8 moles
Step 2:
Determination of the volume occupied by 6.08x10^8 moles of fluorine.
1 mole of any gas occupy 22.4L at stp. This means that 1 mole of fluorine also occupy 22.4L at stp.
Now if 1 mole of fluorine occupies 22.4L at stp,
Then 6.08x10^8 moles of fluorine will occupy = 6.08x10^8 x 22.4 = 1.36x10^10L
Answer:
Gases are easily compressed because of the space between the particles in a gas. ... The pressure decreases because the kinetic energy decreases with the temperature and slower moving particles impact the walls of a contain with less energy.
I believe the complete
given is that the bucket of sand contains 9.5 billion grains of sand. That is:
bucket = 9,500,000,000
grains
and the concentration of
brown sand is 2 ppm:
concentration brown sand =
2 / 1,000,000
Therefore:
brown sand = 9,500,000,000
* (2 / 1,000,000)
<span>brown sand = 19,000 grains</span>
To get the melting point of a solution so, we will use this formula:
ΔT = - mKf
when:
m is molality of the solution
Kf is cryoscopic constant of water = 1.86 C/m
and ΔT is the change in melting point (T2 - 0 °C)
so, now we need to calculate the molality to substitute:
when the molality = moles NaCl / Kg of water
and when moles NaCl = mass / molar mass
= 2.5 g / 58 g/mol
= 0.043 mol
∴ Kg water = volume *density /1000
= 230 mL * 1 g/mL / 1000
= 0.23 Kg
∴ molality = 0.043 / 0.23 =0.187 M
by substitution:
T2-0°C = - 0.187 * 1.86
∴T2 = - 0.348 °C
