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Scorpion4ik [409]
3 years ago
5

SEP Construct Explanations: Food contains chemical potential energy that the body uses. How do you think that the body gains thi

s energy? Propose an explanation.
Chemistry
1 answer:
beks73 [17]3 years ago
8 0

Answer:

Through oxidation of food materials

Explanation:

When living organisms eat, they ingest complex organic food materials. As these food materials enter the body, the process of digestion begins.

Enzymes in the body, located at different parts of the gastrointestinal tract see to the breakdown of these complex food materials ingested. The oxidation of these complex food materials lead to the release of the chemical potential energy stored in them.

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What is the relationship between the concentration and the rate of the reaction?
zalisa [80]

Answer:

When the concentration of all the reactants increases, more molecules or ions interact to form new compounds, and the rate of reaction increases. When the concentration of a reactant decreases, there are fewer of that molecule or ion present, and the rate of reaction decreases.

3 0
3 years ago
Which of the following statements are true regarding the dissociation of Al(NO3)3? Select more than one
Gelneren [198K]

Answer:

There will be one Al3+ ion.

There will be 3 NO3- ions

Explanation:

Dissociation equation:

Al(NO₃)₃   →  Al³⁺ + 3NO₃¹⁻

When aluminium nitrate dissociate it produces one silver ion (Al³⁺) and three (NO₃¹⁻) ions.

Properties of Al(NO₃)₃:

It is inorganic compound having molecular mass 169.87 g/mol.

It is white odor less compound.

Its density is 4.35 g/mL.

Its melting and boiling points are 120°C and 440°C.

It is soluble in water.

It is sued to treat infections.

It is used in the photographic films.

It s toxic and must be handled with great care.

4 0
3 years ago
A similarity ratio of scale factor is the ratio of the lengths of the corresponding of two similar polygons
Arturiano [62]

Answer:

go to hellfhshahahahahahahahahaha  aha

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7 0
3 years ago
With 143.6 grams of acetylene and an excess amount of oxygen gas, what is the percent yeild of carbon dioxide if the actual yiel
nata0808 [166]

Answer:

93.28%

Explanation:

To solve the percent yield we need to find theoretical yield:

<em>Percent yield = Actual Yield (452.78g) / Theoretical yield * 100</em>

<em />

Theoretical yield is obtained converting the mass of acetylene to moles and using the balanced equation determine the moles of CO₂ produced assuming a 100% of reaction:

<em>Moles acetylene (Molar mass: 26.04g/mol)</em>

143.6g C₂H₂ * (1mol / 26.04g) = 5.515 moles C₂H₂

<em>Moles CO₂:</em>

5.515 moles C₂H₂ * (4 moles CO₂ / 2mol C₂H₂) = 11.029moles CO₂

<em>Mass CO₂ (Molar mass: 44.01g/mol):</em>

11.029moles CO₂  * (44.01g / mol) = 485.39g CO₂ is theoretical yield

Percent yield is:

Percent yield = 452.78g / 485.39g * 100

= 93.28%

8 0
3 years ago
Magicians often use ‘flash powder’ in their acts. Flash powder contains 69.0% potassium chlorate (31.9% K, 28.9% Cl, 39.2% O) an
mafiozo [28]

Answer:

\rm K: approximately 22.0\%.

\rm Cl: approximately 19.9\%.

\rm O: approximately 27.0\%.

\rm Al: 31.0\%.

Explanation:

Consider a 100\; \rm g sample. There would be 69.0\% \times 100\; \rm g = 69.0\; \rm g of \rm KClO_{3} and 100.0\; \rm g - 69.0\; \rm g = 31.0\; \rm g of \rm Al.

Out of that 69.0\; \rm g of \rm KClO_{3}:

31.9\% (by mass) would be \rm K: 31.9\% \times 69.0\; \rm g \approx 22.0\; \rm g.

28.9\% (by mass) would be \rm Cl: 28.9\% \times 69.0\; \rm g \approx 19.9\; \rm g.

39.2\% (by mass) would be \rm O: 39.2\% \times 69.0\; \rm g \approx 27.0\; \rm g.

Overall, the composition (by mass) of each element in this mixture would be:

\rm K:

\begin{aligned} & \frac{31.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 31.9\% \times 69.0\% \\ \approx \; & 22.0\%\end{aligned}.

\rm Cl:

\begin{aligned} & \frac{28.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 28.9\% \times 69.0\% \\ \approx \; & 19.9\%\end{aligned}.

\rm O:

\begin{aligned} & \frac{39.2\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 39.2\% \times 69.0\% \\ \approx \; & 27.0\%\end{aligned}.

\rm Al:

\begin{aligned}& \frac{100\; \rm g - 69.0\; \rm g}{100\; \rm g} \\ =\; & 100\% - 69.0\% \\ =\; & 31.0\%\end{aligned}.

7 0
2 years ago
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