Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
Answer: -10
Step-by-step explanation:
Simplifying
-3(y + 5) = 15
Reorder the terms:
-3(5 + y) = 15
(5 * -3 + y * -3) = 15
(-15 + -3y) = 15
Solving
-15 + -3y = 15
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '15' to each side of the equation.
-15 + 15 + -3y = 15 + 15
Combine like terms: -15 + 15 = 0
0 + -3y = 15 + 15
-3y = 15 + 15
Combine like terms: 15 + 15 = 30
-3y = 30
Divide each side by '-3'.
y = -10
Simplifying
Answer:
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Answer:
Step-by-step explanation:
win
There are 3 face cards / suit. Every suit contains a Jack, Queen, and king.
There are 4 suits so the number of face cards is 3*4 = 12
There is 1 ace / suit
There are 4 suits so the number of aces is 1 * 4 = 4
The gain from the face cards = 12 * 13 = 156
The gain from the aces = 4 * 3 = 12
Total gain = 168
Losses
Any other card costs you $5
How many cards is that? 52 - 16 = 36
Each one costs 5 dollars
Total loss = 5 * 36 = 180
So each time you play the game, you can expect to lose 180 - 68 = 12 dollars. You should walk away quickly from this one.
