y=x+14 line 1
y=3x+2 line 2
These are both the equation of lines written in slope intercept form
y=mx+b where m is the slope and the point (0,b) is the y intercept.
The first line has a slope of m=1. The 2nd line has a slope of m=3
Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.
We already have y solved in terms of x from either equation so we can use substitution to solve the system.
Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.
x+14=3x+2
solve for x.
Subtract x from both sides...
14= 3x-x+2
14=2x+2
subtract 2 from both sides
14-2=2x
12=2x
divide both sides by 2
6=x
We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.
y=6+14
y=20
These two lines cross at the point (6,20) which is a point the two lines have in common.
Hope I helped (SharkieOwO)
Now, if the customers left 8.23 extra, based on a percentage of the cost of the meal, namely, the 8.23 is a percent of 49.28, then
if we take 49.28 to be the 100%, how much of a percentage is 8.23?
Answer:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : w^2-36-(-64)=0 Step by step solution : Step 1 : Polynomial Roots Calculator : 1.1 Find roots (zeroes) of : F(w) = w 2 +28 so the answer could be 2.176 or 30.
Answer
l =5
w =2
Area of Rectangle= l × w
= 5 × 2 = 10
Diagram is attached to this:
Step-by-step explanation:
