Consider the intergers as, x and x+1
x+(x+1)=31
2x+1=31
2x=30
x=15
So, (x+1)=(15+1)=16 would be larger number.
Answer:
<u>brainliest plzzzzzzzz</u>
120
Step-by-step explanation:
LCM=1320
(GDC) HCF=12
Another no.=132
let second no. be =A
According to question
First no.×Second no.=HCF×LCM
132×A=12×1320
132×A=15840
A=15840/132
A=120
Other no. is 120
Answer:
Step-by-step explanation:
B. =16x+288x
C. = 1 18 x2+33.52
D.
1752
x
−
162
29
=
−162
29
x+1752
x
=
6(−27x+8468)
29x
=
−162x+50808
29x
F.=
1
12
x+36
1. find equation
general solutions are:

for P(0,-11)

⇒

for p(1,-13)

and

solve for a and b:

the total equation is now:

To find the x-intercept set y=0 and solve for x
Answer:
its d
Step-by-step explanation: