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puteri [66]
3 years ago
12

What is the mass of a 67 dL sample of a salt solution?

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

6733.5 g of NaCl

Explanation:

We can assume that the salt solution is a saline solution which contains NaCl in water at 0.90%, whose density is 1.005 g/ml.

So we need to apply the density concept to solve the question.

Density = mass / volume

We convert dL to mL → 67 dL . 100mL / 1 dL = 6700 mL

Density = mass / volume

Volume . Density = mass

6700 mL . 1.005 g = 6733.5 g of NaCl

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A sample of gas is held at 1000C at a volume of 20 L. If the volume is increased to 40 L, what is the new temperature of the gas
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Answer:

The new temperature will be 2546 K or 2273 °C

Explanation:

Step 1: Data given

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V1/T1 = V2/T2

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⇒with T1 = the initial temperature = 1273 K

⇒with V2 = the increased volume = 40L

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T2 = 40L / (20L/1273K)

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The new temperature will be 2546 K

This is 2546-273 = 2273 °C

Since the volume is doubled, the temperature is doubled as well

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I hope this will help you

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