empirical = C3HF2, molecular = C24H8F16
Explanation:
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carbon hydrogen fluorine
mass 18.24 0.51 16.91
no. of 18.24/12 0.51/1 16.91/19
moles = 1.52 = 0.51 = 0.89
ratio 1.52/0.51 0.51/0.51 0.89/0.51
≈ 3 = 1 ≈ 2
empirical formula = C3HF2
(find number of moles by dividing mass by element's mass number. find ratio by dividing number of moles by overall smallest number of moles, in this case hydrogen)
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let the molecular formula be (C3HF2)n
molar mass = 562.0g/mol
*[3(12) + 1 + 2(19)]n = 562.0
n = 562/75
= 7.49
≈ 8
molecular formula = (C3HF2)8
= C24H8F16
*substitute C, H, and F with their mass numbers
