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Makovka662 [10]
3 years ago
13

Which will result in positive buoyancy and cause the object to float?

Chemistry
2 answers:
otez555 [7]3 years ago
4 0
D. When the buoyant force is greater
Darina [25.2K]3 years ago
3 0
I would say D. Let me know if i am wrong.
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Define and give 3 examples of psychical properties ​
Katen [24]

Answer:

A physical property is any property that is measurable, whose value describes a state of a physical system.

Explanation:

-color

-density

-volume

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3 years ago
Any two properties of ethane​
Pavel [41]

Answer:

colorless odorless gas

two carbon atoms

Explanation:

8 0
3 years ago
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Sound generally travels faster through solids than through gases because the particles (atoms or molecules) of a solid are _____
Tju [1.3M]
Either closer or denser
4 0
3 years ago
A student was asked to determine the densities of the four metals listed. The student was asked to determine the density of an u
Iteru [2.4K]

Answer:

D is correct

Explanation:

because

we know that

density of lead is 11.36 g/cm3

and

density of tin is 7.31 g/cm3

so..

density of alloy by mixing 50/50

=(11.36+7.31)/2 g/cm3

=18.67/2 g/cm3

=9.33 g/cm3

5 0
3 years ago
You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution when ex
mojhsa [17]

Answer:

a. 1.78x10⁻³ = Ka

2.75 = pKa

b. It is irrelevant.

Explanation:

a. The neutralization of a weak acid, HA, with a base can help to find Ka of the acid.

Equilibrium is:

HA ⇄ H⁺ + A⁻

And Ka is defined as:

Ka = [H⁺] [A⁻] / [HA]

The HA reacts with the base, XOH, thus:

HA + XOH → H₂O + A⁻ + X⁺

As you require 26.0mL of the base to consume all HA, if you add 13mL, the moles of HA will be the half of the initial moles and, the other half, will be A⁻

That means:

[HA] = [A⁻]

It is possible to obtain pKa from H-H equation (Equation used to find pH of a buffer), thus:

pH = pKa + log₁₀ [A⁻] / [HA]

Replacing:

2.75 = pKa + log₁₀ [A⁻] / [HA]

As [HA] = [A⁻]

2.75 = pKa + log₁₀ 1

<h3>2.75 = pKa</h3>

Knowing pKa = -log Ka

2.75 = -log Ka

10^-2.75 = Ka

<h3>1.78x10⁻³ = Ka</h3>

b. As you can see, the initial concentration of the acid was not necessary. The only thing you must know is that in the half of the titration, [HA] = [A⁻]. Thus, the initial concentration of the acid doesn't affect the initial calculation.

7 0
3 years ago
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