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babunello [35]
4 years ago
14

9. During vaporization, a substance changes from a liquid to a(n) _______________. (1 point)

Chemistry
1 answer:
Crank4 years ago
3 0
Gas. Is the answer to the question.
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2Li + H2SO4=Li2SO4 + H2 How many liters of hydrogen gas, H2 at STP can be produced from 3.0 moles of Li? The molar volume of a g
Gemiola [76]

Answer:

volume of H_2=33.6 litre

Explanation:

Firstly balance the given chemical equation,

2Li + H_2SO_4=Li_2SO_4 + H_2

From the given balance equation it is clearly that,

2 mole of Li gives  1 mole of H2 gas

2 mole Li⇔1 mole H_2

1 mole Li⇔0.5 mole H_2

3 mole Li⇔1.5 mole H_2

hence

3 mole of Li will give 1.5 mole H2 gas

therefore volume of gas produced from 3 mole Li at STP = 1.5\times22.4 \frac{L}{mol}

volume of H2=33.6 litre

7 0
3 years ago
If you have an atom or copper, an ion of copper and an isotope of copper, what
alexgriva [62]

PLEASE HELP!! PLEASE??

3 0
3 years ago
HURRY I"M BEING TIMED!!!! if an unknown solution has a pH of 2. how would you classify this solution?
Sergeu [11.5K]
An acid, acids have a pH less than 7
7 0
3 years ago
How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in
GaryK [48]

Answer is: 25.84  milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

7 0
4 years ago
Which represents the self ionization of water at 25 degrees
gayaneshka [121]
This question comes with four answer choices:

<span>A. H2O + H2O ⇄ 2H2 + O2

B. H2O + H2O⇄  H2O2 + H2

C. H2O + H2O ⇄ 4H+ + 2O2-

D. H2O + H2O ⇄  H3O+ + OH-

Answer: option </span><span>D. H2O + H2O ⇄  H3O+ + OH-

(the +sign next to H3O is a superscript, as well as the - sing next to OH)

Explanation:

The self-ionization of water, or autodissociation, produces the two ions H3O(+) and OH(-). The presence of ions is what explain the electrical conductivity of pure water.

</span><span>In this, one molecule of H2O loses a proton (H+) (deprotonates) to become a hydroxide ion, OH−. Then, he <span>hydrogen ion, H+</span>, immediately protonates another water molecule to form hydronium, H3O+.
</span>
7 0
3 years ago
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