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hram777 [196]
3 years ago
5

How does the experiment with the marshmallow and the syringe prove that air is matter?

Chemistry
1 answer:
stellarik [79]3 years ago
5 0

solution:

It took mankind tens of thousands of years to figure out that air existed, let alone that it was matter. It was only in recent human history that we figured out anything about air. Proving that air is matter is analogous to today's physics experiments where you cannot see the object of your study, but have to define its properties and its existence from indirect evidence.

We define matter as something which occupies space, is effected by gravity and has weight. Make a vessel that won't collapse if there is no air inside of it. Weigh the vessel when it is full of air. Then pump all of the air out and weigh the vessel again. The difference in weight is the weight of the air.

There is a famous experiment done by Otto Von Guericke in 1654 in Regensburg, Germany. Regensburg was a Roman outpost on the banks of the Danube River. If you ever go there, I highly recommend the Wirstkuke, an 850 year old restaurant near the river. It was there when Guericke was studying air and he may have had a dinner or two there. Anyway, to prove that air exists and has pressure he made a hollow sphere made of two copper halves and sealed it with a gasket. He used an air pump, which he also invented, to pump the air out of the sphere. Air pressure held the two halves of the sphere together. He then took two teams of horses and had them try to pull the sphere apart. They failed. Guericke then opened a valve that let the air back in and that is when the sphere fell apart under its own weight. The sphere was 14" in diameter meaning the air pressure exerted a force of approximately 4.5 tons.

The force would have been the same if one side of the sphere was attached to something fixed, like a really big rock, instead of another team of horses. Guericke might not have understood that or he might have just appreciated the drama of using two teams. Showmanship, you see, is important even in science.

The two most common types of radioactive decay involve the production of alpha particles or beta particles.  

When alpha decay occurs, a daughter element with an atomic number two less than the parent is produced. This is due to the fact that an alpha particle (He nucleus, 2 protons and 2 neutrons) carries away two protons, and the atomic number is the number of protons. In addition, since the alpha particle has four nucleons the mass number of the daughter element goes down by 4.  


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Which electron configuration of the 3 d energy sublevel is the most stable? *
Lostsunrise [7]
Since the chemical definition of "stable" means close to having a full valence shell, the answer is 3d^10.
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3 years ago
For the following reaction, 5.78 grams of chlorine gas are mixed with excess iron. The reaction yields 6.79 grams of iron(III) c
NeX [460]

Answer:

a. Theoretical yield = 8.81 g

b. 77 %

Explanation:

We begin from the reaction:

2Fe (s) + 3Cl₂ (g) → 2FeCl₃ (s)

and the excess is the iron, so the limiting reagent is the chlorine.

We convert mass to moles → 5.78 g / 70.90 g/mol = 0.0815 mol

Ratio is 3:2 so we think this:

From 3 moles of chlorine, I can produce 2 moles of Iron (III) chloride

Then 0.0815 moles would produce (0.0815 . 2) /3 = 0.0543 moles

This is the theoretical yield. We convert the moles to mass:

0.0543 mol . 162.2 g /mol = 8.81 g

If the reaction yields 6.79 g of FeCl₃ and the theoretical yield is 8.81 g ,we can obtain the percent yield: (6.79 / 8.81) . 100 = 77 %

5 0
3 years ago
I need help with this
Shkiper50 [21]
I highly believe it would be D
Because yes it does happen above water but it’s not just that, and the other two don’t seem correct. So sorry it’s not correct but I believe it is D
8 0
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What is the molarity of a solution that contains 0.220 moles KOH in 0.350 L of solution?
Lera25 [3.4K]

Answer:

0.628 M.

Explanation:

In order to solve this problem we need to keep in mind the<em> definition of molarity</em>:

  • Molarity = moles / liters

We are given both the <em>number of moles and the volume of solution</em>, meaning we can now proceed to <u>calculate the molarity</u>:

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3 years ago
Write the expression for the equilibrium constant for the reaction represented by the equation
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3 years ago
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