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hram777 [196]
3 years ago
5

How does the experiment with the marshmallow and the syringe prove that air is matter?

Chemistry
1 answer:
stellarik [79]3 years ago
5 0

solution:

It took mankind tens of thousands of years to figure out that air existed, let alone that it was matter. It was only in recent human history that we figured out anything about air. Proving that air is matter is analogous to today's physics experiments where you cannot see the object of your study, but have to define its properties and its existence from indirect evidence.

We define matter as something which occupies space, is effected by gravity and has weight. Make a vessel that won't collapse if there is no air inside of it. Weigh the vessel when it is full of air. Then pump all of the air out and weigh the vessel again. The difference in weight is the weight of the air.

There is a famous experiment done by Otto Von Guericke in 1654 in Regensburg, Germany. Regensburg was a Roman outpost on the banks of the Danube River. If you ever go there, I highly recommend the Wirstkuke, an 850 year old restaurant near the river. It was there when Guericke was studying air and he may have had a dinner or two there. Anyway, to prove that air exists and has pressure he made a hollow sphere made of two copper halves and sealed it with a gasket. He used an air pump, which he also invented, to pump the air out of the sphere. Air pressure held the two halves of the sphere together. He then took two teams of horses and had them try to pull the sphere apart. They failed. Guericke then opened a valve that let the air back in and that is when the sphere fell apart under its own weight. The sphere was 14" in diameter meaning the air pressure exerted a force of approximately 4.5 tons.

The force would have been the same if one side of the sphere was attached to something fixed, like a really big rock, instead of another team of horses. Guericke might not have understood that or he might have just appreciated the drama of using two teams. Showmanship, you see, is important even in science.

The two most common types of radioactive decay involve the production of alpha particles or beta particles.  

When alpha decay occurs, a daughter element with an atomic number two less than the parent is produced. This is due to the fact that an alpha particle (He nucleus, 2 protons and 2 neutrons) carries away two protons, and the atomic number is the number of protons. In addition, since the alpha particle has four nucleons the mass number of the daughter element goes down by 4.  


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Using the appropriate Ksp values, find the concentration of K+ ions in the solution at equilibrium after 600 mL of 0.45 M aqueou
Alekssandra [29.7K]

Answer:

[K⁺] = 0.107 M

[OH⁻] = 1.13 ×  10⁻⁹ M

Explanation:

600 mL of 0.45 M Cu(NO3)2 gives equal mole of Cu²⁺ and (NO₃)²⁻

⇒ 0.45 × 600 × 10⁻³

= 0.27 moles of Cu²⁺ and (NO₃)²⁻

450 mL of 0.25 M KOH gives equal moles of K⁺ and OH⁻

⇒ 0.25 × 450 × 10⁻³

= 0.1125 moles of K⁺ and OH⁻

Now after mixing 0.1125 moles of OH⁻ precipitates 0.05625 moles of Cu²⁺  (because 1 Cu²⁺  needs 2 OH⁻)

Therefore , moles of remaining Cu²⁺  = 0.27 - 0.05625

=0.21375 moles which is equal to :

⇒ 0.21375/(( 600+450))× 10⁻³

= 0.21375/1050 × 10⁻³

= 0.20357 M

Given that :

(Ksp for Cu(OH)2 is 2.6 ×  10⁻¹⁹)

We know that , Ksp = [Cu²⁺][OH⁻]²

2.6 ×  10⁻¹⁹ = 0.20357 × [OH⁻]²

[OH⁻]² = 2.6 ×  10⁻¹⁹/0.20357

[OH⁻] = 1.13 ×  10⁻⁹ M

[K⁺] = moles of K⁺ /total volume

[K⁺] = 0.1125 / 1050 × 10⁻³

[K⁺] = 0.107 M

6 0
3 years ago
The sum of the ages of a brother and sister is 26.
Goshia [24]
The brother is represented by variable b.
The sister is represented by the variable s. 
This means:
b+s=26
5 0
3 years ago
Which of the following factors would reduce the yield of a reaction?
Olenka [21]

Answer:

B. The reactants form additional unexpected products.

Explanation:

7 0
3 years ago
Which important change in electronic devices, such as televisions and computers, is a result of the use of metalloids as semicon
ss7ja [257]
The answer is A) <span>Electronic devices have become smaller.

</span>
8 0
3 years ago
Read 2 more answers
If 45.0 mL of 6.00M HCl is added to 130 mL of H2O, Determine the molarity of the final solution. (show work)
Ivahew [28]

2.07 M is the molarity of the final solution if 45.0 ml of 6.00M HCl is added to 130 ml of H_{2}O.

Explanation:

Data given:

volume of HCl, V1 = 45 ml

molarity of the HCl solution, M1 = 6 M

final volume of the HCl solution after water is added, V2 = 130 ml

final molarity M2 =?

After the dilution, the molarity of the new solution can be found by using the formula:

M1V1 = M2V2

here M1 and V1 are the molarity and volume for concentrated solution, M2 and V2 represents the diluted solution's molarity and volume.

Applying the formula after rearranging the equation, we get

M2 = \frac{M1V1}{V2}

M2 = \frac{6X45}{130}

M2 = 2.07 M

The final molarity of the HCl solution is 2.07 M

4 0
4 years ago
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