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3 years ago

How many grams of hydrogen gas would be produced from the use of 9.5 moles of aluminum

Chemistry

1 answer:

DIA [1.3K]3 years ago

8 0

Answer:

Identify one disadvantage to each of the following models of electron configuration:

Dot structures

Arrow and line diagrams

Written electron configurations

Explanation:

Identify one disadvantage to each of the following models of electron configuration:

Dot structures

Arrow and line diagrams

Written electron configurations

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a container holds 7.4 moles of gas hydrogen gas makes up 25% of the total moles in the container if the pressure is 1.24 atm wha

Tema [17]

This question is based on Dalton's Law of Partial Pressure which states that "the total pressure of a system of gas is equal to the sum of the pressure of each individual gas (partial pressure).

Now, Partial Pressure of a gas = (mole fraction) × (total pressure)

⇒ Partial Pressure of Hydrogen = $\frac{1}{4}$ × $\frac{1.24}{1}$

= 0.31 atm

Thus the Partial Pressure of Hydrogen in the container is 0.31 atm.

6 0

3 years ago

In class we derived the Gibbs energy of mixing for a binary mixture of perfect gases. We also discussed that the same result is

GaryK [48]

Answer:

Attached below

Explanation:

Free energy of mixing = ΔGmix = Gf - Gi

attached below is the required derivation of the

<u>a) Molar Gibbs energy of mixing</u>

ΔGmix = Gf - Gi

hence : ΔGmix = ∩RT ( X1 In X1 + X2 In X2 + X3 In X3 + ------- )

<u>b) molar excess Gibbs energy of mixing</u>

Ni = chemical potential of gas

fi = Fugacity

N°i = Chemical potential of gas when Fugacity = 1

ΔG = RT In ( a2 / a1 )

4 0

3 years ago

A 45.0-gram sample of copper metal was heated from 20.0°C to 100.0°C. Calculate the heat absorbed, in kJ, by the metal.

s2008m [1.1K]

Answer:

1.386 KJ

Explanation:

From the question given above, the following data were obtained:

Mass (M) of copper = 45 g

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Change in temperature (ΔT) =?

ΔT = T2 – T1

ΔT = 100 – 20

ΔT = 80 °C

Next, we shall determine the heat absorbed by the sample of copper as follow:

Mass (M) of copper = 45 g

Change in temperature (ΔT) = 80 °C

Specific heat capacity (C) of copper = 0.385 J/gºC

Heat absorbed (Q) =..?

Q = MCΔT

Q = 45 × 0.385 × 80

Q = 1386 J

Finally, we shall convert 1386 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

1386 J = 1386 J × 1 KJ /1000 J

1386 J = 1.386 KJ

Thus, the heat absorbed by the sample of the sample of copper is 1.386 KJ.

5 0

2 years ago

The atomic number of an atom is always equal to the total number of

Basile [38]

C is correct. Have a good day!

3 0

3 years ago

Read 2 more answers

True or false a solid has a constant shape and volume

dusya [7]

The answer you are looking for is True

8 0

3 years ago