Answer:
The yield of the product in gram is 
Explanation:
Given that:
the molecular mass weight of the product = 96.2 g/mol
the molecular mass of the reagent (3S)-2,2,-dibromo-3,4-dimethylpentane is 257.997 g
given that the millimoles of the reagent = 2,7 millimoles = 
We know that:
Number of moles = mass/molar mass
Then:
mass = 0.697
Theoretical yield = (number of moles of the product/ number of moles of reactant) × 100
i.e
Theoretical yield = 
where;
and 
Theoretical yield = 
Given that the theoretical yield = 100%
Then:
where,
= derived weight of the product
the molecular mass of the derived product
the molecular mass of the reagent
= weight in a gram of the reagent
it is a great change because the salt goes in and turn the water to salt water
We are given with the equilibrium constant of acid, HF and is asked to calculate the pH of 0.30 M NaF solution. The formula to be followed is
Ka = [H+][F-]/[HF]Ka = 7.2 x 10 -4 = x^2/[0.3-x]x = [H+]= pH = -log (H+) = 1.84
Answer:
What is the molarity of a solution containing 5.00 moles of kcl in 2.00L of solution? Molarity= moles of solute/volume of solution in litre , so the problem looks like this : 7/. 569 , which is equivalent to 12.302 M .
Answer : The mass of 
required is 18.238 grams.
Explanation : Given,
Mass of 
= 83.10 g
Molar mass of = 146 g/mole
Molar mass of = 256.52 g/mole
The balanced chemical reaction is,
First we have to determine the moles of .
Now we have to determine the moles of .
From the balanced chemical reaction we conclude that,
As, 8 moles of produced from 1 mole of
So, 0.569 moles of produced from 
mole of
Now we have to determine the mass of .
Therefore, the mass of required is 18.238 grams.
