Answer:
We use the following formula as given below Use the formula below to find the lone pair on the oxygen atom of the SO3 molecule. L.P (O) = V.E (O) – N.A (S-O) Lone pair on the terminal oxygen atom in SO3 = L.P (O)
Explanation:
Answer:
The mass is 0.855 grams (option A)
Explanation:
Step 1: Data given
aluminium sulfate = Al2(SO4)3
Numer of moles Al2(SO4)3 = 2.50 * 10^-3 moles
atomic mass Al = 26.99 g/mol
atomic mass S = 32.065 g/mol
Atomic mass O = 16 g/mol
Step 2: Calculate molar mass Al2(SO4)3
Molar mass = 2* 26.99 + 3*32.065 + 12*16
Molar mas = 342.175 g/mol
Step 3: Calculate mass Al2(SO4)3
Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass Al2(SO4)3
Mass Al2(SO4)3 = 2.5 *10^-3 moles * 342.175 g/mol
Mass Al2(SO4)3 = 0.855 grams
The mass is 0.855 grams (option A)
You would need to evaporate it
It is organic my friend, have a good day
Explanation:
.
Total mass of oxide z2o3 is 0.797g
mass of element z in the oxide is 0.422g
therefore, mass of oxygen in the oxide is 0.797 - 0.422 = 0.375 g
Number of moles of oxygen in the oxide = 0.375/16 = 0.02344 (atomic mass
of oxygen=16)
From the given chemical formula of oxide, we know that, the element z and
oxygen are in the ratio of 2:3. So, number of moles of z is 0.02344 *2/3 =
0.015625
Hence, atomic mass of z should be = 0.422/0.015625 = 27
Element with atomic mass 27 is Aluminium. The oxide is Al2o3
