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2 years ago

What happens to the density of a fluid as it temperature increases/decreases?

1 answer:

4 0

Let's look at the density of water at 25 deg C and compare that to a higher temperature, 80 deg C. The density decreases from 0.9970 g/mL to 0.9718 as it is heated. This makes sense because, as heat is added to the liquid water, there is greater kinetic energy of the molecules and there are also more vibrations of the water molecules. Together these mean that each H2O unit in liquid water takes up more space as the temperature increases.

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What is the formula for volume using density and mass

lawyer [7]

The definition of density is

Density = (mass) / (volume)

Multiply each side by 'volume' : (density) x (volume) = (mass)

Divide each side by 'density' : Volume = (mass) / (density)

5 0

3 years ago

Read 2 more answers

An ultrasound unit is being used to measure a patient's heartbeat by combining the emitted 2.0 MHz signal with the sound waves r

alexandr402 [8]

Hi there,
for this question we have:
Signal 2.0 MHz = Emitted so we can call it $f_e$
and we need the Reflected = $f_{r}$
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted).
we also know: ΔBeat frequency(max) = 560 Hz = $f_{b}$
so we have:
$f_{e}$ - $f_{r}$ = $f_{b}$
so frequency of Reflected is:
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz = $f_{r}$
now you know that Lambda = v/f
so if we find the lambda with our Emitted then we can find v with the Reflected:
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m
=> $v_{max}$ = (lambda)( $f_{r}$
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s
so the $v_{max}$ is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day

8 0

3 years ago

A wave has a wavelength of 10mm and a frequency of 5 hz what is the speed?

geniusboy [140]

V=fλ
v=5*0.01
Therefore v=0.05

3 0

3 years ago

Read 2 more answers

It is August 1st and you are at a Science Camp in Florida. During an outdoor science quiz, you are asked to identify the tempera

KonstantinChe [14]

Fahrenheit because the boiling point of water is 100 degrees Celsius which is 212 Fahrenheit which is very hot, and that would be about 200 Kelvin so therefore the answer is that the temperature was recorded in Fahrenheit not Kelvin or Celsius

3 0

3 years ago

The aircraft wing from problem 6 experiences temperature extremes that span 210 degrees Celsius. The component for the wing will

ExtremeBDS [4]

Answer:

α = 2,857 10⁻⁵ ºC⁻¹

Explanation:

The thermal expansion of materials is described by the expression

ΔL = α Lo ΔT

α = $\frac{\Delta L}{L_o \ \Delta T}$

in the case of the bar the expansion is

ΔL = L_f - L₀

ΔL= 1.002 -1

ΔL = 0.002 m

the temperature variation is

ΔT = 100 - 30

ΔT = 70º C

we calculate

α = 0.002 / 1 70

α = 2,857 10⁻⁵ ºC⁻¹

5 0

3 years ago