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3 years ago

30 POINTS - will mark brainliest!! 4. write the following in exponential form (d only)

Mathematics

1 answer:

Paul [167]3 years ago

8 0

Answer:

ni had this yesterday hold up gotta find answer

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Given the function y=log3(x+2)-2. List the transformations

slava [35]

Answer:

Exponential transformation.

Step-by-step explanation:

y = log_3 (x + 3) - 2

To transform this into exponential, we have:

Adding 2 to both sides

y + 2 = log_3 (x + 3)

3^(y + 2) = x + 3

x = 3^(y + 2) - 3

4 0

3 years ago

Which expression is equivalent to (7x3)2(x3)?

astraxan [27]

Answer:

(21)+(6) is an equivalent expression

Step-by-step explanation:

(7x3)2(x3)

(21)+(6)

8 0

3 years ago

The number line shows the change in temperature from 7:00 a.M. To 1:00 p.M. Which expression shows how to find the difference be

xz_007 [3.2K]

Answer:

Step-by-step explanation:

The options in the question and the number line are shown in the image attached.

From the options, it is clear that the difference between the temperatures at 7:00 a.M. and 1:00 p.M is;

Temperature at 7:00 a.M - Temperature at 1:00 p.M

We can see from the number line that the temperature at 7:00 a.M = -4

Temperature at 1:00 p.M = 16

difference between the two temperatures = ∣(-4) - 16∣ = 20

4 0

3 years ago

The point (4, –3) is on the terminal side of an angle in standard position. Determine the value of r, and the exact value of sin

viva [34]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

A (4 , -3)

r = ?

sin = ?

cos = ?

tan = ?

Process

1.- Plot the point

This point is in the fourth quadrangle

2.- Calculate r

We have the Opposite side and the Adjacent side

tan Ф = -3/4

tan⁻¹ Ф = Ф = 323.1

Ф = 323.1°

3.- sinФ =

Calculate the hypotenuse

c² = 4² + (-3)²

c² = 16 + 9

c² = 25

c = 5

sinФ = -3/5

cos Ф = 4/5

tan Ф = -3/4

7 0

4 years ago

ANSWER ALL (a-d) FOR 30 POINTS - EASY

djverab [1.8K]

Part a.

<span>The perimeter formula is: </span>P = 2w + 2L

Your answer for part A is P = 2w + 2L

Part b.

They tell us in part b, that:
w = 6L + 20

Substitute that into what we got for part a.

P = 2(6L + 20) + 2L
P = 12L + 40 + 2L
P = 14L + 40

Your answer for partb is P = 14L + 40

Part c.

So we take what we got from part b, and solve for L.

P = 14L + 40
14L = P - 40

$L = \boxed{\frac{P-40}{14}}$

That is your answer for part 3 ^

part d.

Plug in w = 32 into what we first got in part b.

w = 6L + 20
32 = 6L + 20
6L = 12

L = 2

Your answer for part d is L = 2

<span>:D</span>

8 0

3 years ago